我熟悉C。我可以这样写：
uint array[0xFFFF][20];
但我不知道如何在 Csharp 中做到这一点。我尝试了所有 MS 教程和其他教程，但没有运气。
有人可以帮我吗？
问问题
16792 次
6 回答
11
官方教程。基本上，您首先创建“外部”数组，然后循环遍历它，并单独创建每个“内部”数组。
两个例子：
int[][] a = new int[] { new int[]{ 1, 2 }, new int[]{ 3, 4, 5, 6, 7 }};
int[][] c = new int[100][];
for (int i = 0; i < c.length; i++) c[i] = new int[5];
如果您只需要一个二维矩形阵列，您可以使用int[,] b = new int[10, 7];.
于 2012-07-05T10:47:23.327 回答
2
int[][] jaggedArray = new int[3][];
jaggedArray[0] = new int[5];
jaggedArray[1] = new int[4];
jaggedArray[2] = new int[2];
或者
jaggedArray[0] = new int[] { 1, 3, 5, 7, 9 };
jaggedArray[1] = new int[] { 0, 2, 4, 6 };
jaggedArray[2] = new int[] { 11, 22 };
于 2012-07-05T10:47:32.290 回答
1
我不知道在 C 中，但在 c# 中，您可以使用锯齿状数组，例如：
// Declare local jagged array with 3 rows.
int[][] jagged = new int[3][];
// Create a new array in the jagged array, and assign it.
jagged[0] = new int[2];
jagged[0][0] = 1;
jagged[0][1] = 2;
// Set second row, initialized to zero.
jagged[1] = new int[1];
// Set third row, using array initializer.
jagged[2] = new int[3] { 3, 4, 5 };
// Print out all elements in the jagged array.
for (int i = 0; i < jagged.Length; i++)
{
int[] innerArray = jagged[i];
for (int a = 0; a < innerArray.Length; a++)
{
Console.Write(innerArray[a] + " ");
}
Console.WriteLine();
}
于 2012-07-05T10:51:36.320 回答
0
我认为这可能会帮助你
static void Main(string[] args)
{
Console.WriteLine("enter the size of rows");
int n = Convert.ToInt32(Console.ReadLine());
int[][] a = new int[n][];
for (int i = 0; i < a.Length; i++)
{
Console.WriteLine("enter the number of elements for row {0}", i + 1);
int x = Convert.ToInt32(Console.ReadLine());
a[i]=new int[x];
for (int j = 0; j < a[i].Length; j++)
{
a[i][j] = Convert.ToInt32(Console.ReadLine());
}
}
for (int i = 0; i < a.Length; i++)
{
for (int j = 0; j < a[i].Length; j++)
{
Console.Write(a[i][j]+"\t");
}
Console.WriteLine();
}
Console.ReadKey();
}
于 2014-01-26T13:06:38.313 回答
0
namespace jaggedarray
{
class Program
{
static void Main(string[] args)
{
int[][] jagged = new int[5][];
jagged[0] = new int[4] { 22, 33,44,55 };
jagged[1] = new int[1] { 2 };
jagged[2] = new int[4] { 1, 2, 3, 4 };
jagged[3] = new int[2] { 12,13};
jagged[4] = new int[1] {2};
for (int i = 0; i < jagged.Length; i++ ) {
for (int j = 0; j < jagged[i].Length; j++)
{
Console.Write("\t{0}",jagged[i][j]);
}
Console.WriteLine();
Console.WriteLine();
}
// input jagged array
int [][] arrays=new int[5][];
Console.WriteLine("Please Enter the ValueType to make a jagged array:");
arrays[0] = new int[1];
arrays[1] = new int[2];
arrays[2]=new int [3];
arrays[3]=new int [4];
arrays[4] = new int[5];
for (int i = 0; i < arrays.Length;i++ ) {
for (int j = 0; j < arrays[i].Length; j++)
{
arrays[i][j] = Convert.ToInt32(Console.ReadLine());
}
}
Console.WriteLine("This is jagged array::");
for (int i = 0; i < arrays.Length;i++ ) {
for (int j = 0; j < arrays[i].Length;j++ ) {
Console.Write("\t{0}", arrays[i][j]);
}
Console.WriteLine();
}
}
}
}
于 2014-11-13T18:47:50.287 回答
0
创建和显示锯齿状数组的元素
int[][] a = new int[2][];//its mean num of row is 2 which fixed
int choice;//thats i left on user choice that how many number of column in each row he wanna to declare
for (int row = 0; row < a.Length; row++)
{
Console.WriteLine("pls enter number of colo in row {0}", row);
choice = int.Parse(Console.ReadLine());
a[row] = new int[choice];
for (int col = 0; col < a[row].Length; col++)
{
a[row][col] = int.Parse(Console.ReadLine());
}
}
//loop for out put the values of jagged array
for (int row = 0; row < a.Length; row++)
{
for (int col = 0; col < a[row].Length; col++)
Console.Write(a[row][col]+"\t");
Console.WriteLine("");
}
在我使用的插入循环中
a[行].length
代替
a.长度，
背后的原因是每一行都有不同的列数，所以在第二个循环中你必须提到每行的长度
于 2015-01-18T18:24:22.477 回答