android - ANDROID：如果列表视图元素有 url，则使其可点击

Question

我有这个代码：

import android.app.Activity;
import android.app.ListActivity;
import android.os.Bundle;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class Bookmarks extends ListActivity{
@Override
public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.bookmarks);
    Database info=new Database(this);
    info.open();
    String data=info.getData();
    String[] data_array = data.split(",");
    info.close();
    ListView listView1 = (ListView) findViewById(R.id.list_mia);
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1, data_array);
    listView1.setAdapter(adapter);
    listView1.setOnItemClickListener(){
        public void onItemClick(AdapterView<?> a, View v, int position, long id){
            if(data_array[position].startsWith("http://")){
                //do this
            }else{
                //do this
            }
        }
    }
}
}

这是正常工作。如果它有一个网址，我怎样才能使该项目可点击？我在网上尝试了各种帮助，但我无法让它工作！谢谢

Answer 1

试试这个

listView.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView<?> parent, View view,
                int position, long id) {
  if(data_array[position].startsWith("http://")){
//do this
}
else{
//do this
}
 }
});