1

我想实现一个使用mysql进行存储的消息系统。

这是表格：

CREATE TABLE `message` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `id_from` int(10) unsigned NOT NULL,
  `id_to` int(10) unsigned NOT NULL,
  `time` datetime NOT NULL,
  `message` varchar(200) COLLATE utf8_unicode_ci NOT NULL,
  PRIMARY KEY (`id`)
);

id_from 是味精发送者，id_to 是味精接收者。

下面插入 4 条消息用于测试目的：

INSERT INTO `message`(`id`,`id_from`,`id_to`,`time`,`message`) VALUES
(1,1,2,'2012-07-05 12:18:49','msg1'),
(2,2,1,'2012-07-05 12:18:58','msg2'),
(3,3,1,'2012-07-05 12:19:04','msg3'),
(4,1,3,'2012-07-05 12:19:10','msg4');

我想做但没有成功的是构建一个查询，该查询为特定用户的每对（id_from，id_to）获取最后发送或接收的消息。在这种情况下，结果将是：

row1: 2,2,1,'2012-07-05 12:18:58','msg2'
row2: 4,1,3,'2012-07-05 12:19:10','msg4'
4

2 回答 2

0

SELECT * FROM messages WHERE id_from = 1 OR id_to = 1 ？

于 2012-07-05T10:32:38.927 回答
0 
SELECT id, id_from, id_to, time, message
FROM (  SELECT 
        FROM message
        WHERE 1 IN (id_from, id_to) # 1 is user_id in this case
        ORDER BY time DESC) AS h
GROUP BY LEAST(id_from, id_to), GREATEST(id_from, id_to)

获取最后发送和接收的消息的解决方案（虽然不是要求的）

SELECT id, id_from, id_to, time, message
FROM (  SELECT 
        FROM message
        WHERE 1 IN (id_from, id_to) # 1 is user_id in this case
        ORDER BY time DESC) AS h
GROUP BY id_from, id_to

我猜应该这样做。

我确信有“更漂亮”的格式可以捕捉到这一点。

考虑：

SELECT id, 'from' AS type, id_from AS type_id, time, message
FROM message
WHERE id_to = 1
ORDER BY time DESC
LIMIT 1
UNION ALL
SELECT id, 'to', id_to, time, message
FROM message
WHERE id_from = 1
ORDER BY time DESC
LIMIT 1

这会给你：

id  type  type_id  time                 message
3   from  3        2012-07-05 12:19:04  msg3
4   to    3        2012-07-05 12:19:10  msg4
于 2012-07-05T10:38:02.760 回答