2

我正在 Xcode 4.3.3、iOS 5 上开发并使用 Mapkit 库。该应用程序应该在谷歌地图上显示当前位置，获取目的地地址，最后绘制这两点之间的最短路径。

我使用本教程来实现应用程序，我现在有当前位置：http: //blog.objectgraph.com/index.php/2009/04/02/iphone-sdk-30-playing-with-map-kit/

我寻找路由，但我没有找到任何资源。请指导我如何绘制当前位置和目的地之间的最短路径。

谢谢！

4

4 回答 4

4

你可以试试这个只适用于ios 6。 

 Class itemClass = [MKMapItem class];
        if (itemClass && [itemClass respondsToSelector:@selector(openMapsWithItems:launchOptions:)]) {

            CLGeocoder *geocoder = [[CLGeocoder alloc] init];
            CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:getLatitude
                                                                longitude:getLongitude];

            [geocoder reverseGeocodeLocation:newLocation
                           completionHandler:^(NSArray *placemarks, NSError *error) {

                               MKPlacemark *placeMark = [[MKPlacemark alloc] initWithPlacemark:[placemarks objectAtIndex:0]];

                               MKMapItem *mapItem = [[MKMapItem alloc]initWithPlacemark:placeMark];

                               MKMapItem *mapItem2 = [MKMapItem mapItemForCurrentLocation];

                               NSArray *mapItems = @[mapItem, mapItem2];

                               NSDictionary *options = @{
                           MKLaunchOptionsDirectionsModeKey:MKLaunchOptionsDirectionsModeDriving,
                           MKLaunchOptionsMapTypeKey:
                               [NSNumber numberWithInteger:MKMapTypeStandard],
                           MKLaunchOptionsShowsTrafficKey:@YES
                               };

                               [MKMapItem openMapsWithItems:mapItems launchOptions:options];

                           }         ];
        }
        else
        {
            UIAlertView *errorAlert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Failed to Get Your Location"delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
            [errorAlert show];

        }
    }
于 2013-01-04T08:27:34.230 回答
2

你谷歌地图套件和路线？

你会发现这个： http: //inlight.com.au/posts/mapkit，它解释了如何使用谷歌地图并解码响应以提取点以获取路线。

还有一个商业工具包： http: //mtdirectionsk.it/

于 2012-07-05T12:26:20.427 回答
0 
Below ans work for all ios:
   NSString *deviceVersion   = [[UIDevice currentDevice] systemVersion];
    NSLog(@"My Device version is :%@ ",deviceVersion);


    //*********  For ios 6 supporting devices  *********
    if ([deviceVersion isEqualToString:@"6.0"])
    {

        Class itemClass = [MKMapItem class];
        if (itemClass && [itemClass respondsToSelector:@selector(openMapsWithItems:launchOptions:)]) {

            CLGeocoder *geocoder = [[CLGeocoder alloc] init];
            CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:getLatitude
                                                                longitude:getLongitude];

            [geocoder reverseGeocodeLocation:newLocation
                           completionHandler:^(NSArray *placemarks, NSError *error) {

                               MKPlacemark *placeMark = [[MKPlacemark alloc] initWithPlacemark:[placemarks objectAtIndex:0]];

                               MKMapItem *mapItem = [[MKMapItem alloc]initWithPlacemark:placeMark];

                               MKMapItem *mapItem2 = [MKMapItem mapItemForCurrentLocation];

                               NSArray *mapItems = @[mapItem, mapItem2];

                               NSDictionary *options = @{
                           MKLaunchOptionsDirectionsModeKey:MKLaunchOptionsDirectionsModeDriving,
                           MKLaunchOptionsMapTypeKey:
                               [NSNumber numberWithInteger:MKMapTypeStandard],
                           MKLaunchOptionsShowsTrafficKey:@YES
                               };

                               [MKMapItem openMapsWithItems:mapItems launchOptions:options];

                           }         ];
        }
        else
        {
            UIAlertView *errorAlert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Failed to Get Your Location"delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
            [errorAlert show];

        }
    }
    //*********  For other ios supporting devices  *********
    else {

        MKCoordinateRegion region = { {0.0, 0.0 }, { 0.0, 0.0 } };
        region.center.latitude = getLatitude;
        region.center.longitude = getLongitude;

        MKCoordinateRegion currentRegion = { {0.0, 0.0 }, { 0.0, 0.0 } };
        currentRegion.center.latitude = currentLatitude;
        currentRegion.center.longitude = currentLongitude;

        region.span.longitudeDelta = 4.0f;
        region.span.latitudeDelta = 4.0f;
        currentRegion.span.longitudeDelta = 4.0f;
        currentRegion.span.latitudeDelta = 4.0f;

        CLLocationCoordinate2D start = { currentRegion.center.latitude, currentRegion.center.longitude };
        CLLocationCoordinate2D destination = { region.center.latitude, region.center.longitude };

        NSString *googleMapsURLString = [NSString stringWithFormat:@"http://maps.google.com/?saddr=%1.6f,%1.6f&daddr=%1.6f,%1.6f",start.latitude, start.longitude, destination.latitude, destination.longitude];

        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:googleMapsURLString]];

    }

}
于 2013-01-04T08:34:09.993 回答
0

iOS MapKit 不提供应用程序即服务的路由信息​​。相反，您现在的选择是从第三方机制获取路线信息，或者自己构建路线（如果您没有基础街道数据，这基本上是不可能的）。

如果您需要在自己的应用程序中提供路线信息，您可能会将CloudMade视为替代地图系统，或者如果您想利用 Apple 的 Map 进行导航，则可以考虑仅调用 Maps 以路由到某个位置。

如果要调用 Map App 进行导航，则基本上需要打开一个带有源和目标位置的 URL。这是一个例子：

    CLLocationManager *manager = [[[CLLocationManager alloc] init] autorelease];
    CLLocationCoordinate2D currentLocation = [manager location].coordinate;
    NSString *from = [NSString stringWithFormat: @"%f,%f", 
                      currentLocation.latitude, currentLocation.longitude];
    // used to be able to (3.2 iPad) "Current+Location", now we have to send: lat,long
    NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:
                                 NSUTF8StringEncoding];
    NSString *url = [NSString stringWithFormat:
                     @"http://maps.google.com/maps?saddr=%@&daddr=%@", from, encodedAddress];
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]];
于 2012-07-05T11:07:59.300 回答