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我一直在尝试根据不同月份的年龄差异生成报告，目前我知道的解决方案是为每个月和每个年龄差异分别进行单独的 sql 查询，从而为每个月创建 4 个不同的 sql 查询。请让我知道是否可以为每个月创建一个 sql 查询，例如

如果我想为 40 岁以上、50-60 岁、60-70 岁和 80 岁以上的年龄差异生成 JAN 报告

我怎样才能把它放在一个 sql 查询中并从中获得四种不同的结果

类似的东西（只是一个想法）

Select count(Above 40),count(In Between 50 - 60),count (In B/W 60-70), count(above 80) from users
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3 回答 3

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我将 IF() 和 SUM() 一起使用，如下所示：

SELECT SUM(IF(age >= 40,1,0))               AS older40, 
       SUM(IF(age >= 50 and age <= 60,1,0)) AS between50and60
       SUM(IF(age >= 60 and age <= 70,1,0)) AS between60and70
       SUM(IF(age >= 80,1,0))               AS over80

FROM TABLE

IF(expr1,expr2,expr3)参考MySQL的解释，但基本上expr1是条件，expr2是条件为真时的值，expr3是else。对这些使用 1 和 0 允许 SUM() 对记录进行计数。

于 2012-07-04T17:29:04.220 回答
0

尝试类似的东西

Select Range,Count(*) From
(Select 
Case 
When (Age >= 40 and Age < 50) Then 'Above40'
When (Age >= 50 and Age < 60) Then 'Between 50 - 60'
When (Age >= 60 and Age < 70) Then 'In B/W 60-70'
When (Age > 80) Then 'Above 80'
else 'Not Counted'
end as Range
From Users) as Ranges
Group By Range

猜测守卫，因为您似乎有许多间隙和重叠。

于 2012-07-04T17:27:42.767 回答
0 
select *
from (
(select COUNT(Age) as `c1`, '40-50' AS 'freq' from `Users` WHERE Age BETWEEN 40 AND 50)
UNION ALL
(select COUNT(Age)  as `c2`, '50-60' AS 'freq' from `Users` WHERE Age BETWEEN 50 AND 60)
UNION ALL
(select COUNT(Age)  as `c2`, '60-70' AS 'freq' from `Users` WHERE Age BETWEEN 60 AND 70)
) as aliasquery ;
于 2012-07-04T17:41:22.183 回答