4

我正在尝试根据用户选择的字段将 json 值转换为平面 csv。我的 json 看起来像

var data = {
"_index": "test",
"_type": "news",
"_source": {
    "partnerName": "propertyFile 9",
    "relatedSources": "null",
    "entityCount": "50",
    "Categories": {
        "Types": {
            "Events": [{
                "count": 1,
                "term": "Time",
                "Time": [{
                    "term": "Dec 9",
                    "Dec_9": [{
                        "count": 1,
                        "term": "2012"
                    }]
                    }]
                }, {
                "count": 4,
                "term": "News",
                "News": [{
                    "term": "Germany",
                    "Germany": [{
                        "count": 1,
                        "term": "Election"
                    }],
                    "currency": "Euro (EUR)"
                }, {
                    "term": "Egypt",
                    "Egypt": [{
                        "count": 1,
                        "term": "Revolution"
                    }]
                    }]
                }]
            }
    }
}};

我已经能够收集所有出现的值并将其存储为 csv，但我想从根本身保存详细信息..

如果我选择时间，csv 输出应该是这样的，

"test", "news", "propertyFile 9","null", "50", "Events": "Time", "Dec 9", "2012"

是否可以展平 json .. 我将添加 json fiddle 链接以显示我已经用这个东西到达了哪里.. http://jsfiddle.net/JHCwM/

4

6 回答 6

2

您的data值不是 JSON（字符串） - 它是一个对象。有很多方法可以“展平”这个对象，这个小功能可能会有所帮助：

var recMap = function(obj) {
  return $.map(obj, function(val) { 
    return typeof val !== 'object' ? val : recMap(val); 
  });
}

这是它的使用方法。)

于 2012-07-04T16:20:57.210 回答
2

这是将对象展平为键/值对的另一种方法，其中键是属性的完整路径。

let data = {
  pc: "Future Crew",
  retro: {
    c64: "Censor Design",
    amiga: "Kefrens"
  }
};

let flatten = (obj, path = []) => {
  return Object.keys(obj).reduce((result, prop) => {
    if (typeof obj[prop] !== "object") {
      result[path.concat(prop).join(".")] = obj[prop];
      return result;
    }
    return Object.assign(result, flatten(obj[prop], path.concat(prop), result));
  }, {});
}

console.log(
  flatten(data)
);

于 2017-05-10T17:32:06.573 回答
1

有一个 npm 库，有很多选项：https ://mircozeiss.com/json2csv/

# Global install so it can be called from anywhere
$ npm install -g json2csv

## Generate CSV file
$ json2csv -i data.json -o out.csv --flatten-objects

于 2021-01-05T16:04:41.160 回答
0

尝试以下操作：

http://codebeautify.org/view/jsonviewer

使用“导出到 CSV”按钮

于 2014-05-22T12:45:09.700 回答
0

试试看这里：

http://www.zachhunter.com/2011/06/json-to-csv/

和这里：

如何将 JSON 转换为 CSV 格式并存储在变量中

于 2012-07-04T16:17:54.597 回答
0

检查这个以展平Json

// Convert Nested Json to Flat Json
// Check the final json in firebug console.
var fullData = {"data":[{"Vehicle":"BMW","Date":"30, Jul 2013 09:24 AM","Location":"Hauz Khas, Enclave, New Delhi, Delhi, India","Speed":42,"Children":[{"Vehicle":"BMW","Date":"30, Jul 2013 09:24 AM","Location":"Hauz Khas, Enclave, New Delhi, Delhi, India","Speed":42,"Children":[{"Vehicle":"BMW","Date":"30, Jul 2013 09:24 AM","Location":"Hauz Khas, Enclave, New Delhi, Delhi, India","Speed":42,"Children":[]}]},{"Vehicle":"Honda CBR","Date":"30, Jul 2013 12:00 AM","Location":"Military Road,  West Bengal 734013,  India","Speed":0,"Children":[]}]},{"Vehicle":"Honda CBR","Date":"30, Jul 2013 12:00 AM","Location":"Military Road,  West Bengal 734013,  India","Speed":0,"Children":[]},{"Vehicle":"Supra","Date":"30, Jul 2013 07:53 AM","Location":"Sec-45, St. Angel's School, Gurgaon, Haryana, India","Speed":58,"Children":[]},{"Vehicle":"Land Cruiser","Date":"30, Jul 2013 09:35 AM","Location":"DLF Phase I, Marble Market, Gurgaon, Haryana, India","Speed":83,"Children":[]},{"Vehicle":"Suzuki Swift","Date":"30, Jul 2013 12:02 AM","Location":"Behind Central Bank RO, Ram Krishna Rd by-lane, Siliguri, West Bengal, India","Speed":0,"Children":[]},{"Vehicle":"Honda Civic","Date":"30, Jul 2013 12:00 AM","Location":"Behind Central Bank RO, Ram Krishna Rd by-lane, Siliguri, West Bengal, India","Speed":0,"Children":[]},{"Vehicle":"Honda Accord","Date":"30, Jul 2013 11:05 AM","Location":"DLF Phase IV, Super Mart 1, Gurgaon, Haryana, India","Speed":71,"Children":[]}]}
var finalData = [];
loopJson(fullData.data);
function loopJson(data) {
    $.each(data, function(i, e) {
        if (e.Children.length>0) {
            var ccd = e.Children;
            delete e.Children;
            finalData.push(e);
            loopJson(ccd);
        } else {
            delete e.Children;
            finalData.push(e);
        }
    });
}
console.log(finalData);

这是Js小提琴链接http://jsfiddle.net/2nwm43yc/

于 2015-09-08T11:46:53.050 回答