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我在使用 imagecopyresampled 时遇到了一些问题，主要是图像缩放不正确，图像位置错误，边缘有黑色边框。

我设置了以下变量

    $tW = $width; // Original width of image
    $tH = $height; // Orignal height of image

    $w = postvar; // New width
    $h = postvar; // New height
    $x = postvar; // New X pos
    $y = postvar; // New Y pos

然后运行以下

    $tn = imagecreatetruecolor($w, $h);
    $image = imagecreatefromjpeg('filepathhere.jpeg');
    imagecopyresampled($tn, $image, 0, 0, $x, $y, $w, $h, $tW, $tH);

如果有人有任何线索，那将是很大的帮助！谢谢

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1 回答 1

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这里有几个问题。首先，您不应该创建具有指定新高度和宽度的新图像，而是根据原始图像的比例计算它们应该是什么，否则您的缩放图像会失真。例如，下面的代码将创建一个适当调整大小的图像，该图像将适合给定的矩形$w x $h：

$tW = $width;    //original width
$tH = $height;   //original height

$w = postvar;
$h = postvar;

if($w == 0 || $h == 0) {
    //error...
    exit;
}

if($tW / $tH > $w / $h) {
    // specified height is too big for the specified width
    $h = $w * $tH / $tW;
}
elseif($tW / $tH < $w / $h) {
    // specified width is too big for the specified height
    $w = $h * $tW / $tH;
}

$tn = imagecreatetruecolor($w, $h);  //this will create it with black background
imagefill($tn, 0, 0, imagecolorallocate($tn, 255, 255, 255));    //fill it with white;

//now you can copy the original image:
$image = imagecreatefromjpeg('filepathhere.jpeg');
//next line will just create a scaled-down image
imagecopyresampled($tn, $image, 0, 0, 0, 0, $w, $h, $tW, $tH);

现在，如果您只想复制原始图像的某个部分，例如从坐标($x, $y)到右上角，那么您需要将其包含在计算中：

$tW = $width - $x;    //original width
$tH = $height - $y;   //original height

$w = postvar;
$h = postvar;

if($w == 0 || $h == 0) {
    //error...
    exit;
}

if($tW / $tH > $w / $h) {
    // specified height is too big for the specified width
    $h = $w * $tH / $tW;
}
elseif($tW / $tH < $w / h) {
    // specified width is too big for the specified height
    $w = $h * $tW / $tH;
}

$tn = imagecreatetruecolor($w, $h);  //this will create it with black background
imagefill($tn, 0, 0, imagecolorallocate($tn, 255, 255, 255));    //fill it with white;

//now you can copy the original image:
$image = imagecreatefromjpeg('filepathhere.jpeg');
//next line will create a scaled-down portion of the original image from coordinates ($x, $y) to the lower-right corner
imagecopyresampled($tn, $image, 0, 0, $x, $y, $w, $h, $tW, $tH);

如果您提供有关您要实现的目标的更多详细信息，我可能会提供进一步的帮助。

于 2012-07-04T15:01:38.887 回答