sql-server - 对于表中的给定 ID，我们如何获得前后两行？

Question

我有一个 10 行的表

id  values
 1    a
 2    b
 3    c
 4    d
 5    e
 6    f
 7    g
 8    h
 9    i
 10   j

对于@id = 5，我想在之前得到两行，在之后得到两行。

怎么能得到？

Answer 1

Edit This should work as expected (hopefully):

select id, value
from [table]
where id-@id >= -2 
AND   id-@id <=  2 
AND   id-@id <>  0

Here's the running sql: http://sqlfiddle.com/#!6/ca4e5/3/0

Answer 2

一种可能的解决方案：

select *
from table
where id in (3, 4, 6, 7)

如果您使用的是 int 变量 @id，您可以这样做：

select *
from table
where id in (@id-2, @id-1, @id+1, @id+2)

---

要选择前两个：

select top 2 *
from tablename
where id < @id
order by id desc

要选择接下来的两个：

select top 2 *
from tablename
where id > @id
order by id asc