我正在尝试制作一个简单的游戏。
逻辑是这样的:“有五扇门,每扇门编号为 1 到 5。用户将被要求输入任意一个数字。例如,如果他们输入“1”,则会打开 GoldRoom(关联的类将是处理)。”
现在,我定义了一个类,GoldRoom()
,为了测试,输入“1”。处理按预期进行。然而,当我输入“2”作为我的选择时,处理仍然发生,而不是打印语句,即 else 语句没有被执行。
我哪里错了?
#################################
# Learning to make a game#
#################################
# An attempt to make a game
# Each room will be described by a class, whose base class will be Room
# The user will be prompted to enter a number, each number will be assigned with a Room in return
from sys import exit
print "Enter your choice:"
room_chosen = int(raw_input("> "))
if room_chosen == 1:
goldroom = GoldRoom()
goldroom.gold_room()
def dead(why):
print "why, Good Job!"
exit(0)
#class Room(object): #the other room will be derived of this
# pass
class Room(object):
pass
class GoldRoom(Room):
# here the user will be asked with question on how much Gold he wants
print"This room is full of gold. How much do you take!"
next = raw_input("> ")
if "0" in next or "1" in next:
how_much = int(next)
print how_much
else:
dead("Man, learn to type some number")
if how_much < 50:
print "Nice, you are not greedy, you win!"
exit(0)
else:
dead("You greedy bastard!")
#class KoiPondRoom(Room):
# in this room, the user will be made to relax
#class Cthulhu_Room(Room):
# sort of puzzle to get out
#class Bear_Room(Room):
# bear room
#class Dark_Room(Room):
# Dark Room, will be turned into Zombie
#class Dead_Room(Room):
# Those who enter here would be dead
if room_chosen == 1:
goldroom = GoldRoom()
goldroom.gold_room()
else:
print "YOU SUCK!"