我遇到了叉积函数的问题。我需要对每个像素取两个向量的叉积,然后对所有像素的结果求和。
i=1;
[h,w,d] = size(current_vec);
for pxRow = 1:h % fixed pixel row
for pxCol = 1:w % fixed pixel column
for pxsize = 1:d
for r = 1:h % row of distant pixel
for c = 1:w % column of distant pixel
for dpth = 1:d
bfield(c,r,dpth) = cross(current_vec(c,r,dpth),dist_vec(c,r,dpth)); % pythagoras theorem to get distance to each pixel % unit vector from x to s
end
end
end
Bfield(i) = {bfield}; % filling a cell array with results. read below
i = i+1;
end
end
end
??? Error using ==> cross at 37
A and B must have at least one dimension of length 3.
??? Error using ==> cross at 37
A and B must have at least one dimension of length 3.
Error in ==> MAC2 at 71
bfield(c,r,dpth) = cross(current_vec(c,r,dpth),dist_vec(c,r,dpth));
然而,有问题的向量 current_vec 和 dist_vec 如下:
>> size(current_vec)
ans =
35 35 3
>> size(dist_vec)
ans =
35 35 3
就我而言,它们满足了在交叉产品中使用的标准。为什么不是这样?