0

On my website, I have an upload story feature with a user written title and story. It uploads it as a text file in a directory. Is there a way to list the content of these files using php or anything? Also, I'd like to only show like 200 chars of the story, and have a 'show full story' button, that would show the full story (I'll use jQuery for this).

Here is my current code for this, though it doesn't work and i can't figure out the problem :(

<head>
    <style type="text/css">header {font-size:20pt; color:#ff00e8;} footer {text-align: left; font-weight:bold; padding-left: 5px;} article {padding:20px;}</style>    
</head>
<body>
<h2><a href="../php/upload_story.php" style="font-size:15pt; color:#ff00e8; text-decoration: none;" id="tortenetfeltolt">Van  egy  jó  történeted? Írd meg és kikerülhet az oldalra!</a></h2>

<?php
$dataArray = array();
//Number of chars for the string
$num = 200;

//Check if DIR exists
if ($handle = opendir('../php/biralas_tortenetek/')) {
    //Loop over the directory
    while (false !== ($file = readdir($handle))) {
        //Strip out the . and .. files
        if ($file != "." && $entry != "..") {
           // $dataArray[] = array();
            //Store file contents
            $filecontent = file_get_contents($file);
            //Split the content and store in array
            $length = strlen($filecontent);
            $dataArray[] = array(substr($filecontent, 0, $num), substr($filecontent, $num, $length )); 

        }
    }
    //close the dir
    closedir($handle);
}


?>

<?php foreach($dataArray as $data) { ?>
    <div class="visible">
        <?php echo $data[0]; ?>
    </div> 
    <div class="hidden">
        <?php echo $data[1]; ?>
    </div>
<?php } ?>
</body>
4

1 回答 1

2

我看到你用过： substr($filecontent, $num, $length );

在 substr 函数中，第二个参数是你想要开始的位置，第三个是长度。您指定 $num = 200，因此 substr 将从位置 200 开始。

于 2012-07-03T15:05:37.977 回答