java - IndexOutOfBounds with array

Question

Each time I try to run this method

private void resetOdds() {
    mOdds[1] = 0.10;
    mOdds[2] = 0.25;
    mOdds[3] = 0.35;
    mOdds[4] = 0.30;
}

I get an IndexOutOfBounds error. I don't know why, as I supply enough items in the array to change:

private final double[]      mOdds           = { 0.10, 0.25, 0.30, 0.35 };

Does anyone know why I'm getting this error?

score 5 · Accepted Answer

您的索引减少了一个；它应该从 0 开始：

mOdds[0] = 0.10;
mOdds[1] = 0.25;
mOdds[2] = 0.35;
mOdds[3] = 0.30;

score 1 · Accepted Answer

在 Java 中，数组索引从 0 开始。

因此，要访问第 k 个元素，您需要为数组提供第 (k-1) 个索引。

此外，如果您的数组大小为 n，则意味着您的索引从 0 运行到 n-1。

最后，这解决了您的问题：

private void resetOdds() {

mOdds[0] = 0.10;
mOdds[1] = 0.25;
mOdds[2] = 0.35;
mOdds[3] = 0.30;

}

score 1 · Accepted Answer

将代码更改为：

private void resetOdds() {

mOdds[0] = 0.10;
mOdds[1] = 0.25;
mOdds[2] = 0.35;
mOdds[3] = 0.30;

数组在 Java 中基于零。

score 1 · Accepted Answer

private void resetOdds() {

mOdds[0] = 0.10;
mOdds[1] = 0.25;
mOdds[2] = 0.35;
mOdds[3] = 0.30;

}

从 0 开始索引。

score 0 · Accepted Answer

数组是基于 0 的。尝试：

private void resetOdds() {

mOdds[0] = 0.10;
mOdds[1] = 0.25;
mOdds[2] = 0.35;
mOdds[3] = 0.30;

否则，当你去寻找“4”时，由于没有第 5 个元素，你会得到错误。

5 回答 5