我想在显示搜索结果后创建一个弹出表单。由于我对 javascript 知之甚少,如何创建一个弹出表单,在显示结果后会延迟 2 秒?请帮我
当前使用形式
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<table class="form_font" align="center">
<tr>
<td class="title" colspan="2">Log in<br /> <hr style="width:100%; background-color:#000000"></td>
</tr>
<tr>
<td colspan="2"><?php echo $error_MSG;?></td>
</tr>
<tr>
<td colspan="2">Don't have an account? <span class="form_font2"><a href="rates_signup.php">Create one.</a></span></td>
</tr>
<tr>
<td align="right">Email Address:</td><td><input style="width:180px" type="text" name="email"/></td>
</tr>
<tr>
<td align="right">Password:</td><td><input style="width:180px" type="password" name="password"/></td>
</tr>
<tr>
<td></td><td align="right">
<table class="form_font">
<tr>
<td><input type="checkbox" name="remember" value="remember"/></td><td>Remember me (10days)</td>
</tr>
</table>
</td>
</tr>
<tr>
<td></td><td align="right"><input type="submit" class="submitStyle" name="login" value="login"/><input type="submit" name="email_newpass" value="E-mail new password"></td>
</tr>
</table>
</form>
我如何将其更改为: