这是我的代码:
$sqlz = "SELECT t1.user_id, t2.status, t2.email
FROM coverages t1
LEFT JOIN users t2 ON t1.user_id = t2.user_id
GROUP BY t1.user_id
HAVING COUNT(t1.user_id) =".$value;
我想添加这个“ WHERE users.email IS NOT NULL
”当我添加它时,它返回一个白页/没有结果。我知道事实上数据库上至少有 200 个结果包含电子邮件并且符合该标准。
这是我所做但不起作用的示例:
$sqlz = "SELECT t1.user_id, t2.status, t2.email
FROM coverages t1
LEFT JOIN users t2 ON t1.user_id = t2.user_id
WHERE users.email IS NOT NULL
GROUP BY t1.user_id
HAVING COUNT(t1.user_id) =".$value;