php - 如何使用 PHP 获取 PostgreSQL ROW 值

Question

我有这个查询：

SELECT  a.apartment_id, a.building_id, a.apartment_num, a.floor, at.app_type_desc_en AS app_type_desc,
    (SELECT ROW(e.e_name, ot.otype_desc_en)
    FROM    TABLE_TENANTS t INNER JOIN TABLE_OWNERSHIP_TYPES ot ON ot.otype_id=t.ownership_type INNER JOIN TABLE_ENTITIES e ON
t.entity_id = e.entity_id
WHERE   a.apartment_id = t.apartment_id AND t.building_id = a.building_id
ORDER BY t.ownership_type DESC LIMIT 1
    ) AS t_row
    FROM    TABLE_APARTMENTS a INNER JOIN TABLE_APPARTMENT_TYPES at ON at.app_type_id = a.apartment_type LEFT OUTER JOIN TABLE_TENANTS t ON a.building_id = t.building_id AND t.entity_id=1 AND t.status=true LEFT OUTER JOIN TABLE_COMMITTEE_DELEGATE cd ON
     a.building_id = cd.building_id AND cd.entity_id=1 AND cd.status=true
                WHERE a.building_id = 1 AND (t.entity_id=1 OR cd.entity_id=1)
                ORDER BY    a.apartment_num ASC

当我使用 PHP 读取结果时，我使用：

while($ap = pg_fetch_array($_qry)){ 

}

并尝试读取“e_name”，它是 ROW(e.e_name) 的一部分，但我无法成功。

需要你的想法......请。

Answer 1

使用pg_fetch_assoc, 检索 asoc-array 中的数据；但我的建议是 - 使用PDO在 PHP 中使用 db。