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所以我试图从我的 sql 数据库中获取数据，并按与我可能想要制作的某些报告生成相关的某些变量对其进行排序。

<?
$sql = 'SELECT DISTINCT jsfdName.baseData AS Name, jsfdAddr.baseData as Address, jsfdZip.baseData AS Zip, jsfdCity.baseData AS City, jsfdState.baseData AS State,jsfdPhone.baseData AS Phone, jsfdPerson.baseData AS Person, jsfdContacted.baseData AS Contacted
FROM jos_sobipro_field_data AS jsfdName
JOIN jos_sobipro_field_data AS jsfdAddr USING(sid)
JOIN jos_sobipro_field_data AS jsfdZip USING(sid)
JOIN jos_sobipro_field_data AS jsfdCity USING(sid)
JOIN jos_sobipro_field_data AS jsfdState USING(sid)
JOIN jos_sobipro_field_data AS jsfdPhone USING(sid)
JOIN jos_sobipro_field_data AS jsfdPerson USING(sid)
JOIN jos_sobipro_field_data AS jsfdContacted USING(sid)
WHERE jsfdName.fid = 36 AND jsfdAddr.fid = 37 AND jsfdZip.fid=38 AND jsfdCity.fid = 39 AND jsfdState.fid = 41 AND jsfdPhone.fid = 46 AND jsfdPerson.fid = 62 AND jsfdContacted.fid = 61 AND sid > 905';
$rs_result = mysql_query($sql) or die (mysql_error());
$ttl=mysql_num_rows($rs_result);
?>

<center><H2><?=$sitename;?></h2>
<h3>Business Information</h3></center>
<center>Total Entries in Report:&nbsp;<?=$ttl;?></center>
<table border="1" ALIGN = CENTER>
<tr><th>Name</th><th>Address</th><th>Zip</th><th>City</th><th>State</th><th>Phone</th><th>Sales Person</th><th>Contact Method</th></tr>
<?
while ($row = mysql_fetch_assoc($rs_result)) {
?>
  <tr>
  <td><? echo $row[Name]; ?></td>
  <td><? echo $row[Address]; ?></td>
  <td><? echo $row[Zip]; ?></td>
  <td><? echo $row[City]; ?></td>
  <td><? echo $row[State]; ?></td>
  <td><? echo $row[Phone]; ?></td>
  <td><? echo $row[Person]; ?></td>
  <td><? echo $row[Contacted]; ?></td>
  </tr>
<? }; ?></table>

所以我只想显示名字是 Justin、Jeremy 等的销售人员。所以我想我必须在 where 子句中添加另一个条件，比如 AND Person = "Justin"..... 但是那是行不通的。有任何想法吗？

谢谢您的帮助

4

2 回答 2

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在 jsfdPhone.fid = 46 之后你有“AND AND”。

于 2012-07-01T01:53:54.850 回答
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我在 WHERE 子句的末尾添加了另一个 AND。它不能在结束之前，否则它会影响表格并给我错误。所以现在 where 子句看起来像这样......

WHERE jsfdName.fid = 36 AND jsfdAddr.fid = 37 AND jsfdZip.fid=38 AND jsfdCity.fid = 39 AND jsfdState.fid = 41 AND jsfdPhone.fid = 46 AND jsfdPerson.fid = 62 AND jsfdContacted.fid = 61 AND sid > 905 AND jsfdPerson.baseData = "Justin"';

再次感谢各位

于 2012-07-01T02:04:17.500 回答