我想知道如何检查程序是否正在运行,如果没有则运行该程序。
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31124 次
5 回答
8
使用 kill 函数向要检查的进程 ID 发送 0(零)信号。如果进程存在,则函数返回true,否则返回false。
例子:
#-- check if process 1525 is running
$exists = kill 0, 1525;
print "Process is running\n" if ( $exists );
您可以使用系统调用从命令行调用任何程序。这仅在您不需要捕获程序的输出时才有用。
#!/usr/bin/perl
use strict;
use warnings;
my $status = system("vi fred.txt");
或者,如果您不想涉及外壳:
#!/usr/bin/perl
use strict;
use warnings;
my $status = system("vi", "fred.txt");
于 2012-06-30T11:19:56.960 回答
5
与另一个答案类似,但您需要确保并使用“grep -v grep”与 grep 调用本身不匹配。这将确保您在不想时不会评估为真。
use strict;
use warnings;
my($cmd, $process_name) = ("command here", "process name here");
if(`ps -aef | grep -v grep $process_name`) {
print "Process is running!\n";
}#if
else {
`$cmd &`;
}#else
于 2013-05-03T15:55:54.767 回答
3
我尝试了“kill 0 ...”的东西,但是如果您没有对该进程的权限,那将不起作用,因为“kill 0”仅检查是否可以发送信号。由于您没有权限(您的 UID 不是 0 并且进程也不是 UID),因此您将始终为 false。
我还尝试使用 Linux 中的帐户 /proc/ 来检查 PID 目录是否存在,但该部分不是很便携:对 linux 很好,但如果没有额外的爱,将无法在 UNIX 的其他地方真正工作。
所以我写了这个子,HTH:
sub is_running() {
my $pid = shift;
my @proc_data = split(/\s+:\s+/,
`ps uax | awk '{print \$1,":",\$2}' | grep $pid`);
return (@proc_data && $proc_data[1] == $pid) ? $proc_data[0] : undef;
}
用法简单且非常有用,因为它还返回了进程的所有者:
my $pid = 12345;
my $owner = &is_running($pid);
if ($owner) {
print "Process with PID $pid is running and owned by \"$owner\".\n";
}
玩得开心!:)
于 2014-05-22T13:22:41.627 回答
2
如果$pid
为空,则进程未运行:
my $pid = `ps -C $progname -o pid=`; # non-windows solution, sorry
于 2015-03-20T20:02:15.147 回答
0
我们使用它来检查守护进程是否正在运行,基于 Linux 上守护进程启动 pid 文件的内容:
#!/usr/local/bin/perl
use strict;
use warnings;
use feature qw/ say /;
# vars we report
my (
$token, # optional arg - check against cmd_line if specified
$pid_file, # daemon pid-file, e.g. /var/run/mysqld/mysqld.pid
$pid, # the pid to investigate...
$pid_running, # found a pid and it is running
$cmd_line, # cmd_line of the running pid
$result, # 0-OK, 1=FAIL, exit value
$error, # error message if necessary
);
# working vars
my ( $fh, $cmd_file );
die "Daemon pid-file required" unless scalar @ARGV >= 1;
( $pid_file, $token ) = @ARGV;
if ( -s $pid_file ) {
open( $fh, "<", $pid_file ) or die "open $pid_file: $!";
( $pid ) = <$fh>; chomp $pid; close $fh;
$pid_running = kill 0, $pid;
if ( $pid_running ) {
$cmd_file = "/proc/$pid/cmdline";
local($/) = "\0"; # C-String NULL terminated
open( $fh, "<", $cmd_file ) or die "open $cmd_file: $!";
( $cmd_line ) = <$fh>; close $fh;
if ( $cmd_line && $token && $cmd_line !~ m/$token/ ) {
$error = "token not found: $token in $cmd_line";
}
}
else {
$error = "process not found: $pid";
}
}
else {
$error = "file not found: $pid_file";
}
# if TOKEN - OK running process with matching cmdline
$result = $token ? ( $pid_running && $cmd_line && $cmd_line =~ m/$token/ )
: ( $pid_running || 0 );
say "token: ", $token if $token;
say "file: ", $pid_file;
if ( $pid ) {
say "pid: ", $pid;
say "running: ", $pid_running;
say "cmdline: ", $cmd_line if $cmd_line;
}
say "error: ", $error if $error;
say "exit: ", $result ? 'ok' : 'fail';
exit $result;
于 2014-01-15T19:48:29.840 回答