php - COUNT(*) 中的 PHP 错误为 num

Question

我收到 Notice: Use of undefined constant num - assumed 'num'我的代码所遵循的错误

$query = "SELECT COUNT(*) AS num FROM $tableName";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];

如何解决这个问题？

我没有合适的头衔，所以请不要把它改成合适的

score 4 · Accepted Answer

@AkhileshBChandran 给出了一个正确的解决方案。将来，如果您要引用该列，则需要将其放在引号中。

$total_pages = $total_pages['num'];

score 1 · Accepted Answer

1

$total_pages = $total_pages[0];

于 2012-06-30T02:35:29.323 回答

score 0 · Accepted Answer

0

$total_pages = $total_pages['num'];

于 2012-06-30T02:36:47.930 回答

3 回答 3