我一直在尝试实现在线判断,但我被卡住了。我使用 fork 创建一个子进程,然后从子进程中我使用系统命令启动我应该测试的程序。
这是我用来测试分级机的程序。它处于无限循环中,但我只是评论该行以使其工作。
#include <stdio.h>
int main () {
int a, b;
scanf ("%d %d", &a, &b);
while (1);
printf ("%d\n", a + b);
return 0;
}
到目前为止我编码的分级机是
struct timeval start, end;
struct rlimit rl, default_memory, default_time;
getrlimit (RLIMIT_AS, &default_memory);
getrlimit (RLIMIT_CPU, &default_time);
pid_t pid = fork ();
gettimeofday (&start, NULL);
if (pid < 0) printf ("Error\n");
else if (pid == 0) { // child process
if (memory_limit > 0) {
rl.rlim_cur = rl.rlim_max = memory_limit;
setrlimit (RLIMIT_AS, &rl);
}
if (time_limit > 0) {
rl.rlim_cur = rl.rlim_max = time_limit / 1000 + 1;
setrlimit (RLIMIT_CPU, &rl);
}
ptrace (PTRACE_TRACEME, pid, NULL, NULL);
system ("./sum < in.txt > out.txt");
setrlimit (RLIMIT_CPU, &default_time);
setrlimit (RLIMIT_AS, &default_memory);
}
else { // parent process
int *status;
// Is this ok?
// Because here http://linux.die.net/man/2/ptrace it says that
// PTRACE_GETSIGINFO is used to get information about the signal that
// caused the stop. And I'm interested If the program was killed because of
// rlimit (exceeding time or memory limit) or if it was something else.
ptrace (PTRACE_GETSIGINFO, pid, NULL, NULL);
if (wait (status) == -1) return 1; // waiting for the child process to finish
if (WIFSIGNALED (status)) {
int exit_signal = WTERMSIG (status);
printf ("Terminated with signal: %d.\n", exit_signal);
switch (exit_signal) {
case 0:
printf ("OK\n");
break;
case SIGSEGV: // RLIMIT_AS -- SIGSEGV is sent, when the memory limit is exceeded
printf ("Memory Limit Exceeded\n");
break;
case SIGXCPU: // RLIMIT_CPU -- when soft limit is reached SIGXCPU is sent
case SIGKILL: // when hard limit is reached SIGKILL is sent
printf ("Time Limit Exceeded\n");
break;
default: // I didn't handle all the signals, so I made everything else a run time error
printf ("Run Time Error\n");
break;
}
}
ptrace (PTRACE_KILL, pid, NULL, NULL); // Kill the process If it is not killed
gettimeofday (&end, NULL); // This is working fine
double time = (end.tv_sec - start.tv_sec) + 1e-6 * (end.tv_usec - start.tv_usec);
printf ("%lf\n", time);
}