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如果在 FVWM2 中运行,以下代码可以正常工作。但是,如果您将桌面更改为 Gnome,则嵌入的窗口将被破坏而不是被嵌入。

这是为什么? 我错过了什么?...

代码如下,但基本上它所做的只是分叉。在孩子中,我们创建一个 VPython 窗口并让它永远闲置。在父窗口中,我们创建一个 GTK 窗口,找出子窗口的窗口 ID,并尝试将其嵌入到 GTK::Socket 中。

请注意,VPython 部分可能与此无关。

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import subprocess
import sys
import os
import re
import time
from visual import *


def find_window_id (title):
    """Gets the OpenGL window ID."""
    pattern = re.compile('0x[0-9abcdef]{7}')
    proc = subprocess.Popen(['xwininfo', '-name', title],
            stdout=subprocess.PIPE, stderr=subprocess.PIPE)
    errors = proc.stderr.readlines()
    if errors:
        return None
    for line in proc.stdout.readlines():
        match = pattern.findall(line)
        if len(match):
            return long(match[0], 16)
    return None



class Setting ():
    """VPython/OpenGL class."""

    def __init__ (self, w=256, h=256, title='OpenGL via VPython'):
        """Initiator."""
        self.width = w
        self.height = h
        self.title = title
        self.scene = display.get_selected() 
        self.scene.title = self.title
        self.scene.width = self.width
        self.scene.height = self.height
        self.sphere = sphere()



class GTKDisplay ():

    def __init__ (self, winID):
        """Initiator: Draws the GTK GUI."""
        import gtk
        import pygtk
        self.OpenGLWindowID = winID
        window = gtk.Window()
        window.show()
        socket = gtk.Socket()
        socket.show()
        window.add(socket)
        window.connect("destroy", lambda w: gtk.main_quit())
        socket.add_id(long(self.OpenGLWindowID))
        gtk.main()



def main ():
    """Main entry point."""
    name = 'sphere OpenGL window'
    child_pid = os.fork()
    if 0 == child_pid:
        sut = Setting(title=name)
    else:
        winID = None
        while not winID:
            time.sleep(.1)
            winID = find_window_id(name)
        try:
            gui = GTKDisplay(winID)
        except KeyboardInterrupt, err:
            print '\nAdieu monde cruel!'


if __name__ == "__main__":
    main()

PS:是的,这是这个问题的后续。

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