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我将如何做到(这只是示例)不返回错误?
$field_in = this, that $result = mysql_query("SHOW COLUMNS FROM " . $table. " WHERE Field IN ( ".$field_in." )")
$result = mysql_query( "select * from INFORMATION_SCHEMA.COLUMNS c where c.TABLE_SCHEMA = '" . $table. "' and c.COLUMN_NAME IN ( ".$field_in." )")