我制作了一个解析函数的代码,但它不会解析参数(名称,类型)我的代码:
xml_node GCC_XML = doc.child("GCC_XML");
{
for (xml_node Function = GCC_XML.child("Function");Function; Function= Function.next_sibling("Function"))
{
cout<<"Function\n"<<"id= "<<Function.attribute("id").value()<<" , name= "<<Function.attribute("name").value()<<" ,returns: "<<Function.attribute("returns").value()<<Function.child_value("Argument") <<endl;
}
}
那是我要解析的 XML 文件
<?xml version="1.0"?>
<GCC_XML>
<Namespace id="_1" name="::" members="_2 _3 _4 "/>
<Function id="_2" name="main" returns="_5" context="_1" location="f0:8"/>
<Function id="_3" name="a_function" returns="_5" context="_1" location="f0:4">
<Argument name="f" type="_6"/>
<Argument name="e" type="_4"/>
</Function>
<Struct id="_4" name="EmptyClass" context="_1" location="f0:1" members="_7 _8 " bases=""/>
<FundamentalType id="_5" name="int"/>
<FundamentalType id="_6" name="float"/>
<Constructor id="_7" name="EmptyClass" context="_4" location="f0:1">
<Argument name="_ctor_arg" type="_9"/>
</Constructor>
<Constructor id="_8" name="EmptyClass" context="_4" location="f0:1"/>
<ReferenceType id="_9" type="_4c"/>
<File id="f0" name="example1.cxx"/>
</GCC_XML>
问题是它拒绝读取我的结果的函数参数:
Load result: No error
Function
id= _2 , name= main ,returns: _5
Function
id= _3 , name= a_function ,returns: _5
我也试过
cout<<"Function\n"<<"id= "<<Function.attribute("id").value()<<" , name= "<<Function.attribute("name").value()<<" ,returns: "<<Function.attribute("returns").value()<<Function.attribute("Argument") <<endl;
把它给出了相同的结果,只是在参数输出中添加了 0 输出,这表明它没有读取它
把我上面的结果相同