2

我有一个存储以下内容的表：

JobID
ValidationItemID
CreatedBy

我希望能够插入到这个表（一个预定义的模板）中，但只添加不存在的行。我的意思是不存在是 JobID 和 ValidationItemID 的组合使行唯一。我的过程传入了 JobID，但我无法传入验证项 ID，因为我将此列作为模板的一部分...

有这样的效果：

CREATE PROCEDURE insTemplate 
    @JobID varchar(50),
    @Login varchar(50)
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

    -- Insert statements for procedure here
    INSERT INTO
            ValidationItemSignOff
                (
                    JobID,  
                    ValidationItemID,
                    CreatedBy
                )

        SELECT 
        DISTINCT
            @JobID,
            vi.ValidationItemID,
            @Login
        FROM
            RunOffAnswer roa
        INNER JOIN
            Method m ON m.MethodID = roa.MethodID
        INNER JOIN
            RunOffValidationItem vi ON vi.ValidationItemID = m.ValidationItemID
        WHERE
            vi.Inactive=0
            AND NOT EXISTS(SELECT * FROM ValidationItemSignOff WHERE JobID=@JobID AND vi.ValidationItemID ???
END
GO

我不知道如何表达 where 条件，以便它不会重新插入相同的 JobID 和 ValidationItemID。可以说我在桌子里面：

Job      ValidationItem
Job A          1
Job A          2
Job A          5

我有一个包含以下内容的模板：

ValidationItem
1
2
3
4
5
6

当我运行我的存储过程时，它应该只从模板表中插入值 3、4、6，用于作业 id ......所以我需要关于 where 条件的帮助。

我认为我的问题是我不能使用NOT EXISTS，也许我需要重新加入到这个 ValidationItemSignOff 表本身，JobID并且ValidationItemID在哪里ValidationItemID是 NULL，可能是这样的：

CREATE PROCEDURE insTemplate 
    @JobID varchar(50),
    @Login varchar(50)
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

    -- Insert statements for procedure here
    INSERT INTO
            ValidationItemSignOff
                (
                    JobID,  
                    ValidationItemID,
                    CreatedBy
                )

        SELECT 
        DISTINCT
            @JobID,
            vi.ValidationItemID,
            @Login
        FROM
            RunOffAnswer roa
        INNER JOIN
            Method m ON m.MethodID = roa.MethodID
        INNER JOIN
            RunOffValidationItem vi ON vi.ValidationItemID = m.ValidationItemID
        RIGHT OUTER JOIN
            ValidationItemSignOff viso ON viso.JobID = @JobID
                  AND viso.ValidationItemID = vi.ValidationItemID
        WHERE
            vi.Inactive=0
            AND viso.ValidationItemID IS NULL
END
GO

明白了我觉得

用这个替换右连接：

LEFT JOIN
        ValidationItemSignOff viso
        ON  viso.JobID = @JobID
        AND viso.ValidationItemID = vi.ValidationItemID
4

2 回答 2

1

如果您在 2008 年或以上...

MERGE INTO ValidationItemSignOff As Target
USING (SELECT DISTINCT @JobID, vi.ValidationItemID, @Login
         FROM RunOffAnswer roa INNER JOIN 
              Method m
           ON m.MethodID = roa.MethodID INNER JOIN
              RunOffValidationItem vi
           ON vi.ValidationItemID = m.ValidationItemID
        WHERE vi.Inactive = 0) As Source (JobID, ValidationItemID, Login)
   ON Target.JobID = Source.JobID 
  AND Target.ValidationItemID = Source.ValidationItemID
 WHEN NOT MATCHED BY TARGET THEN
      INSERT (JobID, ValidationItemID, CreatedBy)
      VALUES (Source.JobID, Source.ValidationItemID, Source.Login);

免责声明：我可能没有在这里找到语法点。

于 2012-06-28T12:41:18.653 回答
0

我得到了它：

ALTER PROCEDURE insSignOffTemplate 
    @JobID varchar(50),
    @Login varchar(50)
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

    -- Insert statements for procedure here
    INSERT INTO
            ValidationItemSignOff
                (
                    JobID,  
                    ValidationItemID,
                    CreatedBy
                )

        SELECT 
        DISTINCT
            @JobID,
            vi.ValidationItemID,
            @Login
        FROM
            RunOffAnswer roa
        INNER JOIN
            Method m
        ON
            m.MethodID = roa.MethodID
        INNER JOIN
            RunOffValidationItem vi
        ON
            vi.ValidationItemID = m.ValidationItemID
        LEFT JOIN
        ValidationItemSignOff viso
        ON  viso.JobID = @JobID     AND viso.ValidationItemID = vi.ValidationItemID
        WHERE
            vi.Inactive=0
            AND viso.ValidationItemID IS NULL
END
GO
于 2012-06-28T12:53:55.803 回答