我有没有关系的数据。只需要计算 3 个表中的各个列,并将它们作为视图显示在页面上。
这是到目前为止的代码,但不起作用:
SELECT COUNT(cars) AS A,
(SELECT COUNT(boats) FROM tableBoats) AS B,
(SELECT COUNT(trees) FROM tableTrees) AS C,
FROM tableCars
SELECT A, B, C
FROM (SELECT COUNT(cars) as A FROM tableCars) a
CROSS JOIN (SELECT COUNT(boats) as B FROM tableBoats) b
CROSS JOIN (SELECT COUNT(trees) as C FROM tableTrees) c
应该这样做。
假设你有一个像这里这样的表(tableXxx
表有一个名为的字段xxx
),你的查询有一个语法错误,因为后面有一个逗号AS C,
,没有那个逗号,它可以正常工作(至少使用 sqlite,因为 mssql 对我来说在 sqlfiddle 不起作用) :
http://sqlfiddle.com/#!5/5fa6c/3
SELECT COUNT(cars) AS A,
(SELECT COUNT(boats) FROM tableBoats) AS B,
(SELECT COUNT(trees) FROM tableTrees) AS C
FROM tableCars
顺便说一句,您可以将查询简化为
SELECT (SELECT COUNT(cars ) FROM tableCars ) AS A,
(SELECT COUNT(boats) FROM tableBoats) AS B,
(SELECT COUNT(trees) FROM tableTrees) AS C
其他答案也很完美:)
这个怎么样?
SELECT
(SELECT COUNT(*) FROM tableCars) car_count,
(SELECT COUNT(*) FROM tableBoats) boat_count,
(SELECT COUNT(*) FROM tableTrees) tree_count
继 Luc M 的响应之后,它提供了一个列表,与具有单独值的列相比。你可以想象这可能有多么有用......
SELECT C.Accountnum as AccountNum, C.Address as Address, 'C' as Source
From CustTable C
Where C.AccountNum like '000%'
Union All
Select V.Accountnum as AccountNum, V.Name as Address, 'V' as Source
from VendTable V
Where V.AccountNum like 'A%'
SELECT *
FROM
(
SELECT 'Nb cars' as description, COUNT(cars) AS count_item FROM tableCars
UNION ALL
SELECT 'Nb boats' as description, COUNT(boats) AS count_item FROM tableBoats
UNION ALL
SELECT 'Nb tress' as description, COUNT(trees) AS count_item FROM tableTrees
) temp