0

当用户输入值以编辑文本时,我用来替换以下.(dot)代码,(coma)

InputFilter[] FilterArray = new InputFilter[1]; FilterArray[0] = new InputFilter(){

        @Override
        public CharSequence filter(CharSequence arg0, int arg1, int arg2,
                Spanned arg3, int arg4, int arg5) {
            String temp =arg0.toString();
            temp=temp.replace('.',',');

            return temp;
        }

    };

        etxt_kg.setFilters(FilterArray);

上面的代码成功地解释了用户的每个输入。但它什么都不能代替 .(dot)

现在:输入:12.45 输出:1245

我想要什么:输入 12.45 输出:12,45

任何帮助(TIA)

编辑:

问题出在 xml 中。 EditText inputType="number" 。

4

1 回答 1

3

我面临同样的情况。这是一个解决方案

使用以下片段

InputFilter filter = new InputFilter() {

    @Override
    public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
        for (int i = start; i < end; i++) {
            if (source.charAt(i) == '.') {
                return ",";
            }
        }
        return null;
    }
};

EditText editText = (EditText) findViewById(R.id.rg);
editText.setFilters(new InputFilter[] {filter});

下面是我的工作片段

package org.vipul;

import android.app.Activity;
import android.os.Bundle;
import android.text.InputFilter;
import android.text.Spanned;
import android.widget.EditText;

public class AbcActivity extends Activity {
    EditText text;

    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        EditText etxt_kg = (EditText) findViewById(R.id.rg);
        etxt_kg.setMaxHeight(etxt_kg.getHeight());
        InputFilter filter = new InputFilter() {

            @Override
            public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
                for (int i = start; i < end; i++) {
                    if (source.charAt(i) == '.') {
                        return ",";
                    }
                }
                return null;
            }
        };

        // EditText editText = (EditText) findViewById(R.id.rg);
        etxt_kg.setFilters(new InputFilter[] {
            filter
        });

    }
}
于 2012-06-27T07:42:21.613 回答