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我在从数组更新记录时遇到问题。当我去更新时,我只得到第一个数字。例如,如果实际值为 58,我只会插入 5

下面是我的代码,下面有进一步的解释:

$bidArr = $tmpArr;

foreach($tmpArr as $key => $val)
{
$sqlEp = "select sum(endpoints_c), account_id1_c as id from accounts_cstm as ac join accounts as a on a.id = ac.id_c 
where account_id1_c ='$val' and (status_c IN ('active','llp')) and deleted='0'";
$rowEp = $db->query($sqlEp);
$recordEp = $db->fetch_row($rowEp);

$bidArr[$key]['sold_ep_c'] = $recordEp[0];

//print "<pre>EP";
//print_r($recordEp);

}

foreach($bidArr as $key => $val)
{

$data['sold_ep_c'] = $val['sold_ep_c'];
$db->query_update(TABLE_ACC, $data, "id_c='".$key."'");
print "<pre>EP";
print_r($key);
print_r($data);
}

发生的事情是当我取消注释我得到的第一个 print_r 时:

EPArray ( [0] => 16 [1] => 51067d38

哪个是对的。但是,如果我将其注释掉并取消注释第二个,我会得到:

51067d38 ( [sold_ep_c] => 1 )

为什么这会剥离第一个数字?

4

1 回答 1

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根据聊天...您的数组未初始化。 $bidArr[$key] = array();在第一个循环中!

于 2012-06-27T03:31:52.520 回答