我需要一些帮助来生成与所需阶梯输出匹配的 MS SQL 2012 查询。行按一个日期范围（帐户提交日期月份）汇总数据，列按另一个日期范围（付款日期月份）汇总数据
表 1：帐户跟踪为收款设置的帐户。
CREATE TABLE [dbo].[Accounts](
[AccountID] [nchar](10) NOT NULL,
[SubmissionDate] [date] NOT NULL,
[Amount] [money] NOT NULL,
CONSTRAINT [PK_Accounts] PRIMARY KEY CLUSTERED (AccountID ASC))
INSERT INTO [dbo].[Accounts] VALUES ('1000', '2012-01-01', 1999.00)
INSERT INTO [dbo].[Accounts] VALUES ('1001', '2012-01-02', 100.00)
INSERT INTO [dbo].[Accounts] VALUES ('1002', '2012-02-05', 350.00)
INSERT INTO [dbo].[Accounts] VALUES ('1003', '2012-03-01', 625.00)
INSERT INTO [dbo].[Accounts] VALUES ('1004', '2012-03-10', 50.00)
INSERT INTO [dbo].[Accounts] VALUES ('1005', '2012-03-10', 10.00)
表 2：Trans跟踪付款
CREATE TABLE [dbo].[Trans](
[TranID] [int] IDENTITY(1,1) NOT NULL,
[AccountID] [nchar](10) NOT NULL,
[TranDate] [date] NOT NULL,
[TranAmount] [money] NOT NULL,
CONSTRAINT [PK_Trans] PRIMARY KEY CLUSTERED (TranID ASC))
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-01-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-02-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-03-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-02-20', 325.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-04-20', 25.00)
INSERT INTO [dbo].[Trans] VALUES (1003, '2012-03-24', 625.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-03-28', 31.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-04-12', 5.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-08', 7.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-28', 3.00)
这是所需的输出应该是什么样子
*Total Payments in Each Month*
SubmissionYearMonth TotalAmount | 2012-01 2012-02 2012-03 2012-04
--------------------------------------------------------------------
2012-01 2099.00 | 300.00 300.00 300.00 0.00
2012-02 350.00 | 325.00 0.00 25.00
2012-03 685.00 | 656.00 15.00
前两列将 Account.Amount 按月分组。
最后 4 列按月份对放置在当前行的给定月份的帐户的 Tran.TranAmount 求和。
我一直在处理的查询感觉很接近。我只是没有正确的滞后。这是我目前正在使用的查询：
Select SubmissionYearMonth,
TotalAmount,
pt.[0] AS MonthOld0,
pt.[1] AS MonthOld1,
pt.[2] AS MonthOld2,
pt.[3] AS MonthOld3,
pt.[4] AS MonthOld4,
pt.[5] AS MonthOld5,
pt.[6] AS MonthOld6,
pt.[7] AS MonthOld7,
pt.[8] AS MonthOld8,
pt.[9] AS MonthOld9,
pt.[10] AS MonthOld10,
pt.[11] AS MonthOld11,
pt.[12] AS MonthOld12,
pt.[13] AS MonthOld13
From (
SELECT Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2) AS SubmissionYearMonth,
SUM(Amount) AS TotalAmount
FROM Accounts
GROUP BY Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2)
)
AS AccountSummary
OUTER APPLY
(
SELECT *
FROM (
SELECT CASE WHEN DATEDIFF(Month, SubmissionDate, TranDate) < 13
THEN DATEDIFF(Month, SubmissionDate, TranDate)
ELSE 13
END AS PaymentMonthAge,
TranAmount
FROM Trans INNER JOIN Accounts ON Trans.AccountID = Accounts.AccountID
Where Convert(Char(4),Year(TranDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, TranDate)),2)
= AccountSummary.SubmissionYearMonth
) as TransTemp
PIVOT (SUM(TranAmount)
FOR PaymentMonthAge IN ([0],
[1],
[2],
[3],
[4],
[5],
[6],
[7],
[8],
[9],
[10],
[11],
[12],
[13])) as TransPivot
) as pt
它产生以下输出：
SubmissionYearMonth TotalAmount MonthOld0 MonthOld1 MonthOld2 MonthOld3 ...
2012-01 2099.00 300.00 NULL NULL NULL ...
2012-02 350.00 325.00 300.00 NULL NULL ...
2012-03 685.00 656.00 NULL 300.00 NULL ...
至于列日期标题。我不确定这里最好的选择是什么。我可以添加一组额外的列并创建一个可以在结果报告中使用的计算值。