我在函数中有这段代码。我想打印y
这里的值。
if (x1 < 0 || y1 < 0) {
// Vertical lign outside of layer
if (dx == 0 && y1 < 0) {
return GKIT_NOERR;
}
float m = dy / dx;
float t = y1 - m * x1;
float x = -t / m;
float y = m * x + t;
printf("Hello %s. You are %f years old.\n", "Niklas", y);
}
但是我遇到了分段错误。它根本没有任何价值,可以打印为浮点数。我可以将其更改为%d
或类似的,效果很好。
int val = (int) y;
printf("Hello %s. You are %d years old.\n", "Niklas", val);
知道 Segfault 来自哪里吗?
编辑:完成功能。
// coding: ascii
// author: Niklas Rosenstein
// e-mail: rosensteinniklas@googlemail.com
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "gkit/defines.h"
#include "gkit/utils.h"
#include "gkit/graphicslayer.h"
#define SWAP_IF_NECCESSARY(x1, y1, x2, y2) \
if (x2 < x1 && y2 < y1) { \
int temp = x2; \
x2 = x1; \
x1 = temp; \
temp = y2; \
y2 = y1; \
y1 = temp; \
}
/* Based on Bresenhams line algorithm. */
int gk_GraphicsLayer_drawLine(gk_GraphicsLayer* layer, gk_Color* color,
int x1, int y1, int x2, int y2,
gk_ColorBlendProc blend, gk_float opacity) {
SWAP_IF_NECCESSARY(x1, y1, x2, y2);
float dx = x2 - x1;
float dy = y2 - y1;
float cx = x1;
float cy = y1;
// Figure out where to start in case x1 or y1 are outside of the layer.
if (x1 < 0 || y1 < 0) {
// Vertical lign outside of layer
if (dx == 0 && y1 < 0) {
return GKIT_NOERR;
}
// The function's slope (m)
// ------------------------
float m = dy / dx;
// Find the y-axis intersection (t)
// -------------------------------
// y = mx + t =>
// y - mx = t
float t = y1 - m * x1;
// Compute the root of the function (N)
// ------------------------------------
// 0 = mx + t =>
// mx = -t =>
// x = -t / m
float x = -t / m;
float y = m * x + t;
printf("Hello %s. You are %f years old.\n", "Niklas", y);
}
int incx = GKIT_SIGNUM(dx);
int incy = GKIT_SIGNUM(dy);
if (dx < 0) { dx = -dx; }
if (dy < 0) { dy = -dy; }
int pdx, pdy;
int ddx, ddy;
int es, el;
ddx = incx;
ddy = incy;
if (dx > dy) {
pdx = incx;
pdy = 0;
es = dy;
el = dx;
}
else {
pdx = 0;
pdy = incy;
es = dx;
el = dy;
}
float err = el / 2.0;
#define SET_PIXEL(x, y) \
do { \
gk_Color* c = GKIT_GRAPHICSLAYER_ACCESSPIXEL(layer, (int)x, (int)y); \
if (blend != Null) { \
gk_Color t = *c; \
blend(color, &t, c, opacity); \
} \
else { \
*c = *color; \
} } while (0)
SET_PIXEL(cx, cy);
int t;
for (t=0; t < el; t++) {
err -= es;
if (err < 0) {
err += el;
cx += ddx;
cy += ddy;
}
else {
cx += pdx;
cy += pdy;
}
SET_PIXEL(cx, cy);
}
#undef SET_PIXEL
return GKIT_NOERR;
}
编辑:完整的堆栈跟踪:
#0 0xb7e68cb0 ___printf_fp(fp=0xb7fc3a20, info=0xbffff684, args=0xbffff6f8) (printf_fp.c:844)
#1 0xb7e63ab0 _IO_vfprintf_internal(s=0xb7fc3a20, format=<optimized out>, ap=0xbffff750 "\001") (vfprintf.c:1623)
#2 0xb7e6cc2f __printf(format=0x8049da0 "Hello %s. You are %f years old.\n") (printf.c:35)
#3 0x8049143 gk_GraphicsLayer_drawLine(layer=0x804d008, color=0xbffff810, x1=-20, y1=-10, x2=49, y2=200, blend=0, opacity=0) (/home/niklas/git/c-gkit/gkit/graphicslayer.c:180)
#4 0x8049ba4 test_drawLine() (/home/niklas/git/c-gkit/main.c:46)
#5 0x8049c80 main() (/home/niklas/git/c-gkit/main.c:68)
编辑:请注意,将它放在 if 子句之后或之前时printf()
确实有效。即类似的东西
printf("Foo: %f\n", 1.0);
// Figure out where to start in case x1 or y1 are outside of the layer.
if (x1 < 0 || y1 < 0) {
// Vertical lign outside of layer
if (dx == 0 && y1 < 0) {
return GKIT_NOERR;
}
确实有效,但移动if 子句printf()
内部会产生分段错误。
更新:根据TED的回答,我进行了一些测试,结果如下:
问题似乎是比较操作 ( <
) 的结果。我可以
if (True) { printf("%f", 53.3); }
但我做不到
if (x1 < 0 || y1 < 0) { printf("%f", 53.3); }
// nor
if (x1 < 0) { printf("%f", 53.3); }
// nor
int x_smaller = x1 < 0;
if (x_smaller) { printf("%f", 53.3); }
有趣的是,这有效:
int x_smaller = x1 < 0;
int y_smaller = y1 < 0;
x_smaller = y_smaller = 1;
if (x_smaller || y_smaller) { printf("%f", 53.3); }
结论:操作的结果x1 < 0
和y1 < 0
在 if 子句中测试的结果printf()
失败。问题是:
- 大福?为什么会这样?
- 我该如何解决?
如果您对整个代码感兴趣,我不介意分享它。它在github 上。这是一个 Code::Blocks 项目。唯一的包含路径必须是文件夹的父目录gkit
。