将结果复制Map
到 的实现中SortedMap
,例如TreeMap
。
像这样(按键排序):
SharedPreferences myPrefs = this.getSharedPreferences("myPrefs", MODE_WORLD_READABLE);
TreeMap<String, ?> keys = new TreeMap<String, Object>(myPrefs.getAll());
for (Map.Entry<String, ?> entry : keys.entrySet()) {
Log.i("map values", entry.getKey());
//some code
}
要按值排序并且 不丢失任何键值对(因为 Map 很容易允许重复值映射到不同的键),您需要首先将其转换为 aList
并对其进行排序。
List<Pair<Object, String>> sortedByValue = new LinkedList<Pair<Object,String>>();
for (Map.Entry<String, ?> entry : keys.entrySet()) {
Pair<Object, String> e = new Pair<Object, String>(entry.getValue(), entry.getKey());
sortedByValue.add(e);
}
// Pair doesn't have a comparator, so you're going to need to write one.
Collections.sort(sortedByValue, new Comparator<Pair<Object, String>>() {
public int compare(Pair<Object, String> lhs, Pair<Object, String> rhs) {
// This is a naive and shitty comparator, but it works for
// arbitrary objects. Sort of. Tweak depending on the order you need.
String sls = String.valueOf(lhs.first);
String srs = String.valueOf(rhs.first);
int res = sls.compareTo(srs);
// Sort on value first, key second
return res == 0 ? lhs.second.compareTo(rhs.second) : res;
}
});
for (Pair<Object, String> pair : sortedByValue) {
Log.i("map values", pair.first + "/" + pair.second);
}