**接下来的代码应该将数据从 webService 解析到 textView；
问题：IOEXception问：我怎样才能解决异常并让我的程序正常工作？？**所以任何人都可以帮助我，因为我尝试了很多来自网络的示例代码，但对我没有任何帮助
@Override
public class NewParsActivity extends Activity {
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button b;
/** Called when the activity is first created. */
static final String baseUrl="http://www.androidpeople.com/wp-content/uploads/2010/06/example.xml";
TextView tv;
EditText ed,ed2;
tv=(TextView)findViewById(R.id.text);
ed=(EditText)findViewById(R.id.edt);
b=(Button) findViewById(R.id.button1);
ed2=(EditText) findViewById(R.id.editText1);
try{
SAXParserFactory spf=SAXParserFactory.newInstance();
SAXParser sp=spf.newSAXParser();
XMLReader xr=sp.getXMLReader();
URL link=new URL(baseUrl);
handlXml doingWork=new handlXml();
xr.setContentHandler(doingWork);
xr.parse(new InputSource(link.openStream()));
String information=doingWork.getInformation();
tv.setText(information);
}catch(Exception e){
tv.setText("Error");
}
//
public class handlXml extends DefaultHandler {
One item=new One();
public String getInformation(){
return item.DataToString();
}
@Override
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
// TODO Auto-generated method stub
if(localName.equals("website")){
String uniN=attributes.getValue("category");
item.setName(uniN);
}
}
}
//
public class One {
String UName;
public void setName(String n){
UName=n;
}
public String DataToString()
{
return "In"+UName;
}
}