0

我有以下aspx:

 <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" 
                BorderStyle="None" Font-Names="Verdana" Font-Size="12px" 
                OnSelectedIndexChanged="GridView1_SelectedIndexChanged" ShowHeader="False"                     
                GridLines="None" EnableModelValidation="True" Width="22%" >
                    <RowStyle BorderStyle="None"  Height="40px" HorizontalAlign="Left"/>                            
                        <Columns>                                           
                            <asp:HyperLinkField Text="&lt;img src='../Images/CMM/download.png'/&gt;"></asp:HyperLinkField>                                                                
                            <asp:ButtonField CommandName="Select" DataTextField="codigo" DataTextFormatString="{0:d}"
                                ItemStyle-HorizontalAlign="Left" ControlStyle-Font-Underline="true">
                                <ControlStyle Font-Underline="True" />
                            </asp:ButtonField>
                        </Columns>
                    <EditRowStyle BorderStyle="None" />
                    <AlternatingRowStyle BorderStyle="None" />
                 </asp:GridView>                          

我有以下 apsx.cs 文件代码:

protected void GridView1_SelectedIndexChanged(object sender, EventArgs e)
{                  
        CallSaveAs(GridView1.SelectedRow.Cells[1].Text);   
}

GridView1.SelectedRow.Cells[1].Text 是空的,但我可以在 Debug 上看到它

我也试过:

ButtonField bf = (ButtonField)GridView1.SelectedRow.Cells[1].Controls[0];

但我无法将类型“System.Web.UI.Control”转换为“System.Web.UI.WebControls.ButtonField”

终于找到了解决办法:

    protected void GridView1_SelectedIndexChanged(object sender, EventArgs)
    {        
        LinkButton lb = (LinkButton)GridView1.SelectedRow.Cells[1].Controls[0];              
        CallSaveAs(lb.Text);   
    }
4

2 回答 2

1

我认为 ButtonField 呈现为多个控件,而您想要的是 LinkBut​​ton 所以您需要做的是引用第二个控件并将其转换为 LinkBut​​ton 像这样 -

LinkButton btn = (LinkButton)GridView1.SelectedRow.Cells[1].Controls[1];
string text = btn.Text;
于 2012-06-26T10:59:03.797 回答
0

ButtonField bf = (ButtonField)GridView1.SelectedRow.Cells[2].Controls[0];

现在试试....

不同数据源的相同条件在这里工作....

于 2012-06-26T10:36:45.177 回答