我有一个最奇怪的问题。我有一个脚本可以计算一个月中的当前工作日以及该月的工作日总数。例如，今天 6 月 25 日，脚本将输出“day 17/21”。
奇怪的是，对于 12 日为星期一的月份，从 12 日到月底，当前工作日显示为比实际工作日少 0.0417 天。例如，对于 3 月 11 日（星期日），它显示“7/22”。但是对于 3 月 12 日，它显示“7.95833333/22”
下面是我在互联网某处的帖子中找到的脚本代码。除了这个奇怪的场合，每隔一段时间它都能完美运行。
//##########################################################
//Date Calculations
//##########################################################
$datepicker = $_POST['datepicker'];
$dpyear = date("Y", strtotime($datepicker));
$dpmonth = date("m", strtotime($datepicker));
$dpday = date("d", strtotime($datepicker));
$end = date('Y/m/d', mktime(0, 0, 0, $dpmonth, $dpday, $dpyear)); // seconds * minutes * hours * days
$first = date('Y/m/d', mktime(0, 0, 0, $dpmonth, 1, $dpyear));
$firstOfYear = date('Y/m/d', mktime(0, 0, 0, 1, 1, $dpyear));
$last = date('Y/m/d', mktime(0, 0, 0, $dpmonth + 1, 0, $dpyear));
$firstprevyear = date('Y/m/d', mktime(0, 0, 0, $dpmonth, 1, $dpyear-1));
$lastprevyear = date('Y/m/d', mktime(0, 0, 0, $dpmonth + 1, 0, $dpyear-1));
$prevyearmonth = date('M\'y', mktime(0, 0, 0, $dpmonth + 1, 0, $dpyear-1));
$prevyeardate = "sojd.InvoiceDate >= '$firstprevyear' and sojd.InvoiceDate <= '$lastprevyear' ";
$mtddaterange = "sojd.InvoiceDate >= '$first' and sojd.InvoiceDate <= '$end' ";
$ytddaterange = "sojd.InvoiceDate >= '$firstOfYear' and sojd.InvoiceDate <= '$end' ";
if (date("w", strtotime($datepicker)) == 1) { // if today is Monday, combine weekend and Monday's numbers
$startDate = date('Y/m/d', mktime(0, 0, 0, $dpmonth, $dpday - 2, $dpyear));
$prevdaterange = "sojd.InvoiceDate >= '$startDate' and sojd.InvoiceDate <= '$end'";
$daterange = "sojd.InvoiceDate >= '$startDate' and sojd.InvoiceDate <= '$end'";
$params = array($startDate, $end);
} else {
$prevdaterange = "sojd.InvoiceDate = '$end' ";
$daterange = "sojd.InvoiceDate = '$end'";
$params = array($end);
}
$holidays=array("2012-01-02","2012-05-28","2012-07-04","2012-09-03","2012-11-22","2012-12-25");
function getWorkingDays($startDate,$endDate,$holidays){
// do strtotime calculations just once
$endDate = strtotime($endDate);
$startDate = strtotime($startDate);
//The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24
//We add one to inlude both dates in the interval.
$days = ($endDate - $startDate) / 86400 + 1;
$no_full_weeks = floor($days / 7);
$no_remaining_days = fmod($days, 7);
//It will return 1 if it's Monday,.. ,7 for Sunday
$the_first_day_of_week = date("N", $startDate);
$the_last_day_of_week = date("N", $endDate);
//---->The two can be equal in leap years when february has 29 days, the equal sign is added here
//In the first case the whole interval is within a week, in the second case the interval falls in two weeks.
if ($the_first_day_of_week <= $the_last_day_of_week) {
if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--;
if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--;
}
else {
// (edit by Tokes to fix an edge case where the start day was a Sunday
// and the end day was NOT a Saturday)
// the day of the week for start is later than the day of the week for end
if ($the_first_day_of_week == 7) {
// if the start date is a Sunday, then we definitely subtract 1 day
$no_remaining_days--;
if ($the_last_day_of_week == 6) {
// if the end date is a Saturday, then we subtract another day
$no_remaining_days--;
}
}
else {
// the start date was a Saturday (or earlier), and the end date was (Mon..Fri)
// so we skip an entire weekend and subtract 2 days
$no_remaining_days -= 2;
}
}
//The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder
//---->february in none leap years gave a remainder of 0 but still calculated weekends between first and last day, this is one way to fix it
$workingDays = $no_full_weeks * 5;
if ($no_remaining_days > 0 )
{
$workingDays += $no_remaining_days;
}
//We subtract the holidays
foreach($holidays as $holiday){
$time_stamp=strtotime($holiday);
//If the holiday doesn't fall in weekend
if ($startDate <= $time_stamp && $time_stamp <= $endDate && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7)
$workingDays--;
}
return $workingDays;
}
$currSalesDay = getWorkingDays($first,$end,$holidays);
$totalSalesDay = round(getWorkingDays($first,$last,$holidays),0);