4

不幸的是，cygwin GCC 4.5.3 pthread 库实现不支持 POSIX 标准函数

int pthread_mutex_timedlock(pthread_mutex_t* mutex, struct timespec* abstime);

有没有人知道如何在互斥体包装类中为此方法实现一个好的解决方法？可能pthread_mutex_trylock()与（基于毫秒的）nanosleep()调用一起使用？我对后一个想法没有很好的感觉，但无论如何 C++ 实现可能看起来像这样：

bool MyPosixMutexWrapper::try_lock(const TimeDuration<>& timeout)
{
    if(valid)
    {
        if(timeout == TimeDuration<>::Zero)
        {
             if(pthread_mutex_trylock(&mutexHandle) == 0)
             {
                 return true;
             }
        }
        else
        {
            struct timespec now;
            clock_gettime(CLOCK_REALTIME,&now);
            TimeDuration<> tnow(now);
            tnow += timeout;
            struct timespec until = tnow.getNativeValue();
#if defined(_POSIX_TIMEOUTS)
            if(pthread_mutex_timedlock(&mutexHandle,&until) == 0)
            {
                return true;
            }
#else
            long milliseconds = timeout.milliseconds();
            while(milliseconds > 0)
            {
                 if(pthread_mutex_trylock(&mutexHandle) == 0)
                 {
                     return true;
                 }

                 struct timespec interval;
                 struct timespec remaining;
                 interval.tv_sec = 0;
                 interval.tv_nsec = 1000000;
                 do
                 {
                     remaining.tv_sec = 0;
                     remaining.tv_nsec = 0;
                     if(nanosleep(&interval,&remaining) < 0)
                     {
                         if(errno == EINTR)
                         {
                             interval.tv_sec = remaining.tv_sec;
                             interval.tv_nsec = remaining.tv_nsec;
                         }
                         else
                         {
                             return false;
                         }
                     }
                     clock_gettime(CLOCK_REALTIME,&now);
                     tnow = TimeDuration<>(now);
                     if(tnow >= TimeDuration(until))
                     {
                          return pthread_mutex_trylock(&mutexHandle) == 0;
                     }
                } while(remaining.tv_sec > 0 || remaining.tv_nsec > 0);
                --milliseconds;
            }
#endif
        }
    }
    return pthread_mutex_trylock(&mutexHandle) == 0;
}

有没有人对此代码有更好的想法或改进？

4

1 回答 1

3

我的建议是使用 apthread_cond_timedwait来模仿你的定时锁。这里的诀窍timed_mutex_是永远不会保持很长时间，因为等待timed_cond_会释放锁。在设置或取消设置timed_mutex_后也会立即释放。locked_

struct MutexGuard {
    pthread_mutex_t &mutex_;
    MutexGuard (pthread_mutex_t &m) : mutex_(m) {
        pthread_mutex_lock(&mutex_);
    }
    ~MutexGuard () {
        pthread_mutex_unlock(&mutex_);
    }
};

struct TimedMutex {
    pthread_mutex_t timed_mutex_;
    pthread_cond_t timed_cond_;
    bool locked_;

    TimedMutex ()
        : timed_mutex_(), timed_cond_(), locked_(false) {
        pthread_mutex_init(&timed_mutex_, 0);
        pthread_cond_init(&timed_cond_, 0);
    }

    ~TimedMutex () {
        pthread_cond_destroy(&timed_cond_);
        pthread_mutex_destroy(&timed_mutex_);
    }

    int lock (const struct timespec *t) {
        MutexGuard g(timed_mutex_);
        while (locked_) {
            int r = pthread_cond_timedwait(&timed_cond_, &timed_mutex_, t);
            if (r < 0) return r;
        }
        locked_ = true;
        return 0;
    }

    void lock () {
        MutexGuard g(timed_mutex_);
        while (locked_) {
            pthread_cond_wait(&timed_cond_, &timed_mutex_);
        }
        locked_ = true;
    }

    void unlock () {
        MutexGuard g(timed_mutex_);
        locked_ = false;
        pthread_cond_signal(&timed_cond_);
    }
};
于 2012-06-28T22:55:49.527 回答