php - 从mysql中拉取今天输入的数据

Question

我在这里没有看到明显的东西吗，似乎无法使其正常工作...

if (($_GET['date']=='today'))
{ 
    $today = date('Y-m-d', strtotime('today'));     
    $query = "SELECT * FROM contacts WHERE (contacttype = 'Buyer' OR "
           . "contacttype = 'Seller' OR contacttype = 'Buyer / Seller' OR "
           . "contacttype = 'Investor') AND date = '$today' ORDER BY date DESC";
}

谢谢！

Answer 1

你甚至不需要用 PHP 告诉 MySQL 今天是什么，它已经知道了！

SELECT * FROM contacts WHERE (contacttype = 'Buyer' OR contacttype = 'Seller' OR contacttype = 'Buyer / Seller' OR contacttype = 'Investor') AND date = DATE(NOW()) ORDER BY date DESC

假设 WHERE 子句中的所有其他条件都是正确的，它将起作用。请参阅 MySQL 的date()和now()参考。

Answer 2

SELECT *
FROM contacts
WHERE (contacttype = 'Buyer'
        OR contacttype = 'Seller'
        OR contacttype = 'Buyer / Seller'
        OR contacttype = 'Investor')
    AND DATE = CUR_DATE()
ORDER BY DATE DESC`

Answer 3

请尝试以下方法：

where DATE(dt) = DATE(NOW())