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当用户点击一个按钮时，如何在用户墙上发布一些东西（可能是一个 php 处理的图像或一些文本）。例如，假设一个 facebook 用户安装了我的应用程序，然后它会显示一些处理过的图像，然后如果用户希望发布，他单击发布按钮并发布到他的墙上，否则不会。我面临的困难是从一个页面转到另一个页面（如从 index.php 到 upload.php），传输access_token，以及如何进行 api 调用以从 upload.php 上传图像，如果我必须进行上传。 php 作为 index.php 以便它可以重新验证用户？

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1 回答 1

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你听起来真的很困惑。

如果您将文件命名index.php为upload.php.

我不明白为什么您需要手动处理访问令牌。使用 PHP SDK，它会自动为您完成。PHP SDK 使用该$_SESSION变量来存储它。否则，您可以在 URL 中将其作为参数传递，例如：

upload.php?access_token=SOMETHING_REALLY_SECRET

不过我不建议这样做，因为它会使您的网站很容易受到攻击。

PHP SDK 文档中有一个完整的示例：

<?
  // Remember to copy files from the SDK's src/ directory to a
  // directory in your application on the server, such as php-sdk/
  require_once('php-sdk/facebook.php');

  $config = array(
    'appId' => 'YOUR_APP_ID',
    'secret' => 'YOUR_APP_SECRET',
    'fileUpload' => true,
  );

  $facebook = new Facebook($config);
  $user_id = $facebook->getUser();

  $photo = './mypic.png'; // Path to the photo on the local filesystem
  $message = 'Photo upload via the PHP SDK!';
?>
<html>
  <head></head>
  <body>

  <?
    if($user_id) {

      // We have a user ID, so probably a logged in user.
      // If not, we'll get an exception, which we handle below.
      try {

        // Upload to a user's profile. The photo will be in the
        // first album in the profile. You can also upload to
        // a specific album by using /ALBUM_ID as the path 
        $ret_obj = $facebook->api('/me/photos', 'POST', array(
                                         'source' => '@' . $photo,
                                         'message' => $message,
                                         )
                                      );
        echo '<pre>Photo ID: ' . $ret_obj['id'] . '</pre>';

      } catch(FacebookApiException $e) {
        // If the user is logged out, you can have a 
        // user ID even though the access token is invalid.
        // In this case, we'll get an exception, so we'll
        // just ask the user to login again here.
        $login_url = $facebook->getLoginUrl( array(
                       'scope' => 'photo_upload'
                       )); 
        echo 'Please <a href="' . $login_url . '">login.</a>';
        error_log($e->getType());
        error_log($e->getMessage());
      }   

      echo '<br /><a href="' . $facebook->getLogoutUrl() . '">logout</a>';
    } else {

      // No user, print a link for the user to login
      // To upload a photo to a user's wall, we need photo_upload  permission
      // We'll use the current URL as the redirect_uri, so we don't
      // need to specify it here.
      $login_url = $facebook->getLoginUrl( array( 'scope' => 'photo_upload') );
      echo 'Please <a href="' . $login_url . '">login.</a>';

    }

  ?>

  </body>
</html>
于 2012-06-24T18:22:29.233 回答