0

我正在努力使以下工作：

# prev
SELECT klha.buyerID < PARAMETER_1

    FROM agents AS v

    LEFT JOIN seller_authorized AS klhs 
        ON klhs.agent= v.agentID 
        AND klhs.iln = v.seller
        AND v.`status` = 'auth'

    LEFT JOIN cust_list AS klha 
        ON klha.buyerID  = klhs.userID
        AND klha.accountNo = klhs.accountNo
        WHERE v.iln = PARAMETER_2
        AND klhs.acccountNo IS NOT NULL

    ORDER BY klha.buyerID 
    LIMIT 1 
;

结尾

左连接正在工作，因为我在另一个过程中使用它们来选择所有相关记录。问题在于我尝试选择上一条记录。

我传入了一个buyerID，需要取回上一条记录的ID。

问题：
谁能指出正确的语法？

编辑：
如果我在 MySQL 中运行它，我会得到“0”作为结果集

谢谢！

解决方案：
让它像这样工作：

# prev
SELECT klha.buyerID

    FROM agents AS v

    LEFT JOIN seller_authorized AS klhs 
        ON klhs.agent= v.agentID 
        AND klhs.iln = v.seller
        AND v.`status` = 'auth'

    LEFT JOIN cust_list AS klha 
        ON klha.buyerID  = klhs.userID
        AND klha.accountNo = klhs.accountNo
        WHERE v.iln = PARAMETER_2
        AND klhs.acccountNo IS NOT NULL
        AND klha.buyerID < PARAMETER_1

    ORDER BY klha.buyerID 
    LIMIT 1 
;

比想象的容易:-) 谢谢@Henrique Ordine

4

1 回答 1

1

如果我正确理解您的需要，将此条件添加到您的 where 子句应该可以解决问题：

和 klha.buyerID = (从购买者 ID < PARAMETER_1 的代理中选择 max(buyerID))

像这样：

SELECT klha.buyerID 

    FROM agents AS v

    LEFT JOIN seller_authorized AS klhs 
        ON klhs.agent= v.agentID 
        AND klhs.iln = v.seller
        AND v.`status` = 'auth'

    LEFT JOIN cust_list AS klha 
        ON klha.buyerID  = klhs.userID
        AND klha.accountNo = klhs.accountNo
    WHERE v.iln = PARAMETER_2
      AND klhs.acccountNo IS NOT NULL
      and klha.buyerID = (select max(buyerID) from agents 
                            where buyerID < PARAMETER_1)

    ORDER BY klha.buyerID 
    LIMIT 1
于 2012-06-24T07:25:17.140 回答