我采用了这篇文章中的代码并制作了这个小提琴。尝试单击第一行，然后按住 shift 单击最后一行。如果你注意到这段代码做得很好，除了最后一行，你点击的那一行，没有被选中。我一直在为此挠头。谁能帮我更改代码，以便多选也选择最后一行？
谢谢！
问问题
2988 次
5 回答
6
尝试替换这个：if ((shouldSelectRow = id == startID || shouldSelectRow)) {用这个：
if ((shouldSelectRow = id == startID || shouldSelectRow) && (id != rowid)){
于 2012-06-24T11:05:33.557 回答
6
我同意 Michael Gendin 的观点，即您不应选择 id 等于 的行rowid。这是你的主要错误。不过，我会重写演示的大部分代码以使用行的 DOM 元素的rowIndex，而不是枚举网格的所有行。此外，在您当前的代码中，在 IE 中选择文本并不方便，因此我建议您将其删除。您在这里找到的修改后的演示我使用了以下beforeSelectRow回调代码：
beforeSelectRow: function (rowid, e) {
var $this = $(this), rows = this.rows,
// get id of the previous selected row
startId = $this.jqGrid('getGridParam', 'selrow'),
startRow, endRow, iStart, iEnd, i, rowidIndex;
if (!e.ctrlKey && !e.shiftKey) {
$this.jqGrid('resetSelection');
} else if (startId && e.shiftKey) {
$this.jqGrid('resetSelection');
// get DOM elements of the previous selected and the currect selected rows
startRow = rows.namedItem(startId);
endRow = rows.namedItem(rowid);
if (startRow && endRow) {
// get min and max from the indexes of the previous selected
// and the currect selected rows
iStart = Math.min(startRow.rowIndex, endRow.rowIndex);
rowidIndex = endRow.rowIndex;
iEnd = Math.max(startRow.rowIndex, rowidIndex);
for (i = iStart; i <= iEnd; i++) {
// the row with rowid will be selected by jqGrid, so:
if (i != rowidIndex) {
$this.jqGrid('setSelection', rows[i].id, false);
}
}
}
// clear text selection
if(document.selection && document.selection.empty) {
document.selection.empty();
} else if(window.getSelection) {
window.getSelection().removeAllRanges();
}
}
return true;
}
于 2012-06-24T13:49:36.793 回答
1
添加$('#grid').disableSelection();以删除烦人的文本选择
于 2013-04-03T00:15:01.733 回答
0
正如奥列格的回答中所讨论的，这是一个调整后的 beforeSelectRow ，它执行附加的选择。
在我的例子中，我们的用户选择了一堆要导出的行，所以额外的选择通常并不意味着他们想要开始一个新的选择。
beforeSelectRow: function(rowid, e) {
var $this = $(this), rows = this.rows,
// get id of the previous selected row
startId = $this.jqGrid('getGridParam', 'selrow'),
startRow, endRow, iStart, iEnd, i, rowidIndex;
if (!e.ctrlKey && !e.shiftKey) {
//intentionally left here to show differences with
//Oleg's solution. Just have normal behavior instead.
//$this.jqGrid('resetSelection');
} else if (startId && e.shiftKey) {
//Do not clear existing selections
//$this.jqGrid('resetSelection');
// get DOM elements of the previous selected and
// the currect selected rows
startRow = rows.namedItem(startId);
endRow = rows.namedItem(rowid);
if (startRow && endRow) {
// get min and max from the indexes of the previous selected
// and the currect selected rows
iStart = Math.min(startRow.rowIndex, endRow.rowIndex);
rowidIndex = endRow.rowIndex;
iEnd = Math.max(startRow.rowIndex, rowidIndex);
// get the rowids of selected rows
var selected = $this.jqGrid('getGridParam','selarrrow');
for (i = iStart; i <= iEnd; i++) {
// if this row isn't selected, then toggle it.
// jqgrid will select the clicked on row, so just ingore it.
// note that we still go <= iEnd because we don't know which is start or end.
if(selected.indexOf(rows[i].id) < 0 && i != rowidIndex) {
// true is to trigger onSelectRow event, which you may not need
$this.jqGrid('setSelection', rows[i].id, true);
}
}
}
// clear text selection (needed in IE)
if(document.selection && document.selection.empty) {
document.selection.empty();
} else if(window.getSelection) {
window.getSelection().removeAllRanges();
}
}
return true;
}
于 2013-01-03T22:43:07.187 回答
0
Oleg 的解决方案不适用于所有选择模式（上/下）。感谢他的部分解决方案。
我用这段代码纠正了这个问题：
您需要 2 个变量来存储当前的起始行 ID 和结束行 ID。另一个用于存储选择的一面。
var _currentStartSelectRow, _currentEndSelectRow, _isSideDown = null;
beforeSelectRow 回调的代码调用：
beforeSelectRow: function (rowid, e) {
var $this = $(this), rows = this.rows,
// get id of the previous selected row
previousId = $this.jqGrid('getGridParam', 'selrow'),
previousRow, currentRow;
if (!e.ctrlKey && !e.shiftKey) {
_isSideDown = null;
$this.jqGrid('resetSelection');
} else if (previousId && e.shiftKey) {
$this.jqGrid('resetSelection');
// get DOM elements of the previous selected and the currect selected rows
previousRow = rows.namedItem(previousId);
currentRow = rows.namedItem(rowid);
if (previousRow && currentRow) {
//Increment
if (previousRow.rowIndex < currentRow.rowIndex) {
if (_isSideDown == false || _isSideDown == null) {
_currentStartSelectRow = previousRow.rowIndex;
_currentEndSelectRow = currentRow.rowIndex;
}
else {
_currentEndSelectRow = currentRow.rowIndex;
}
_isSideDown = true;
}
//Decrement
else {
if (_isSideDown == null) {
_currentStartSelectRow = currentRow.rowIndex;
_currentEndSelectRow = previousRow.rowIndex;
_isSideDown = false;
}
else if (_isSideDown == true) {
if (currentRow.rowIndex < _currentStartSelectRow) {
_currentStartSelectRow = currentRow.rowIndex;
_isSideDown = false;
}
else {
_currentEndSelectRow = currentRow.rowIndex;
}
}
else {
_currentStartSelectRow = currentRow.rowIndex;
}
}
for (i = _currentStartSelectRow; i <= _currentEndSelectRow; i++) {
// the row with rowid will be selected by jqGrid, so we don't need to select him:
if (i != currentRow.rowIndex) {
$this.jqGrid('setSelection', rows[i].id, false);
}
}
}
}
return true;
},
于 2018-01-05T11:19:59.140 回答