我拥有的 Mysqli 代码没有显示成功搜索的结果。该查询在语句方面是正确的，因为这是在 MYSQL 中测试的。但是当尝试使用 mysqli 时，我似乎无法在成功搜索后显示结果。我究竟做错了什么？在进行错误报告时我没有收到任何错误，并且查询中没有拼写错误。我不知道是不是因为查询需要在循环之外，或者我错误地绑定了参数或类似的东西，但是代码曾经在旧的 mysql 代码中工作，但我无法让它在 mysqli 中工作（不能由于我的 PHP 版本，使用 PDO）
应用程序的 URL 在这里。如果您输入“AAD”，它会说它找不到任何结果，而实际上它应该这样做，因为数据库中有 5 行包含术语“AAD”
下面是表单代码：
<form action="previousquestions.php" method="get">
<p>Search: <input type="text" name="questioncontent" value="<?php echo $questioncontent; ?>" onchange="return trim(this)" /></p>
<p><input id="searchquestion" name="searchQuestion" type="submit" value="Search" /></p>
</form>
下面是整个 mysqli 代码及其注释
//Get terms entered in the textbox
$questioncontent = (isset($_GET['questioncontent'])) ? $_GET['questioncontent'] : '';
$searchquestion = $questioncontent;
$terms = explode(" ", $searchquestion);
//Start of query
$questionquery = "
SELECT q.QuestionId, q.QuestionContent, o.OptionType, an.Answer, r.ReplyType,
FROM Answer an
INNER JOIN Question q ON q.AnswerId = an.AnswerId
JOIN Reply r ON q.ReplyId = r.ReplyId
JOIN Option_Table o ON q.OptionId = o.OptionId
WHERE ";
$i=0;
//loop through each term
foreach ($terms as &$each) {
$each = '%'.$each.'%';
$i++;
//if only 1 term entered then perform this LIKE statement
if ($i == 1){
$questionquery .= "q.QuestionContent LIKE ? ";
} else {
//If more than 1 term then add an OR statement
$questionquery .= "OR q.QuestionContent LIKE ? ";
}
}
//group terms by terms entered in chronilogical order
$questionquery .= "GROUP BY q.QuestionId, q.SessionId ORDER BY "; $i = 0; foreach ($terms as $each) {
$i++;
//if multiple terms, then display results that contains all terms first, then start displaying other results by knocking off 1 term at a time
if ($i != 1)
$questionquery .= "+";
$questionquery .= "IF(q.QuestionContent LIKE ? ,1,0)";
}
$questionquery .= " DESC ";
//bind the parameters by the amount of terms there are
$types = "";
for($i = 0; $i<sizeof($terms); $i++) {
$types .= "s";
}
//merge the parameters and the terms
$eachterms = array_merge( array($types), $terms);
//prepare quert
$stmt=$mysqli->prepare($questionquery);
//in array call all the parameters and its terms
call_user_func_array(array($stmt, 'bind_param'), $eachterms);
//execute terms
$stmt->execute();
//bind the result
$stmt->bind_result($dbQuestionContent);
//display the results of the successful search
$output = "";
$output .= "
<table border='1' id='resulttbl'>
<tr>
<th class='questionth'>Question</th>
</tr>
";
while ($stmt->fetch()) {
$output .= "
<tr>
<td class='questiontd'>{$dbQuestionContent['QuestionContent']}</td>
</tr>";
}
$output .= " </table>";
echo $output;
}