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短信；投递；"+99999999999";"";"";"2012.06.23 09:21";"";"xxxxxxxxxxxx xxxxxxxx,
xxxxxxxxxxxx
xxxxxxxxxxxx
xxxxxxxxxxxx"

我需要任何不以“sms;deliver;”开头的行 被添加到上一行。即得到这样一条线：

短信；投递；"+99999999999";"";"";"2012.06.23 09:21";"";"xxxxxxxxxxxx xxxxxxxx, xxxxxxxxxxxx xxxxxxxxxxxx xxxxxxxxxxxx"

^ 那是一行。此外，删除/替换 xxxxx(content) 部分中的任何双引号也会很有帮助。

短信;发送;“+99999999999”;“”;“”;“2012.06.23 09:21”;“”;“xxxxxxxxxxxxxxx xxxxxxxx, xxxxxxxxxxxx xxxxxxxxxxxx”xxxxxx“xxxxxxxx”

所以上面的行会被转换成这个（双引号转换成单引号）：

短信；发送；"+99999999999";"";"";"2012.06.23 09:21";"";"xxxxxxxxxxxxxxx xxxxxxxx, xxxxxxxxxxxx xxxxxxxxxxxx 'xxxx'xxxxxxxx"

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2 回答 2

3

以下sed命令似乎可以满足您的需要（已编辑：sed开头的简短命令用于过滤引号）：

sed '/^sms;deliver;/!'"y/\"/'/" yourfile | sed -n '/^sms;deliver;/!b;:r;${p;b};N;/\nsms;deliver;/!{s/\n//;br};P;s/.*\n//;br'

一个简短的解释：

sed -n '# not print by default
/^sms;deliver;/!b # if line not starting with the pattern, goto end
:r #label r
${p;b} # if last line, print & exit
N # read new line, append to pattern space
/\nsms;deliver;/!{s/\n//;br} # if appended line doesn't start with pattern,
                             # remove newline & goto r
P # print everything up to the newline
s/.*\n//;br # remove what was just printed, goto r'

sed开头的仅更改为"不'与sms;delivered;

于 2012-06-23T14:32:51.587 回答
2

这可能对您有用：

sed ':a;$!N;/\nsms;deliver;/!s/\n//;ta;:b;s/\(;".*\)"\([^";]*\)"\([^";]*"\)$/\1'\''\2'\''\3/;tb;P;D' file

编辑：

的问题的测试数据"：

echo 'sms;deliver;"+99999999999";"";"";"2012.06.23 09:21";"";"xxxxxxxxxxxxx xxxxxxxx, xxxxxxxxxxxx xxxxxxxxxxxx "xxxx"xxxxxxxx"' >/tmp/a
sed ':a;$!N;/\nsms;deliver;/!s/\n//;ta;:b;s/\(;".*\)"\([^";]*\)"\([^";]*"\)$/\1'\''\2'\''\3/;tb;P;D' /tmp/a
sms;deliver;"+99999999999";"";"";"2012.06.23 09:21";"";"xxxxxxxxxxxxx xxxxxxxx, xxxxxxxxxxxx xxxxxxxxxxxx 'xxxx'xxxxxxxx"
sed 's/xx/"&"/g' /tmp/a >/tmp/b
sed ':a;$!N;/\nsms;deliver;/!s/\n//;ta;:b;s/\(;".*\)"\([^";]*\)"\([^";]*"\)$/\1'\''\2'\''\3/;tb;P;D' /tmp/b
sms;deliver;"+99999999999";"";"";"2012.06.23 09:21";"";"'xx''xx''xx''xx''xx''xx'x 'xx''xx''xx''xx', 'xx''xx''xx''xx''xx''xx' 'xx''xx''xx''xx''xx''xx' ''xx''xx'''xx''xx''xx''xx'"
于 2012-06-23T14:43:00.367 回答