我尝试将jsf和spring集成,但是tomcat有错误404。我真的很困惑,我找不到问题所在。我将 default.xhtml 放在 web-content 中,但 tomcat 说:description 请求的资源(/jsfandspring/faces/default.xhtml)不可用。UserBoImpl.java
package p;
public class UserBoImpl implements UserBo{
String name;
public void setName(String name) {
this.name = name;
}
public String getMessage() {
return "hi: " + name;
}
}
用户Bean.java
package p;
import java.io.Serializable;
import p.UserBo;
//DI via JSF managed bean
public class UserBean implements Serializable{
//DI via Spring
UserBo userBo;
public void setUserBo(UserBo userBo) {
this.userBo = userBo;
}
public String printMsgFromSpring() {
return userBo.getMessage();
}
}
默认.xhtml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:h="http://java.sun.com/jsf/html"
>
<h:body>
<h1>JSF 2.0 + Spring Example</h1>
#{user.printMsgFromSpring()}
</h:body>
</html>
应用程序上下文.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean id="UserBo" class="p.UserBoImpl">
<property name="name" value="Samira" />
</bean>
</beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">
<display-name>jsfandspring</display-name>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<context-param>
<description>State saving method: 'client' or 'server' (=default). See JSF Specification 2.5.2</description>
<param-name>javax.faces.STATE_SAVING_METHOD</param-name>
<param-value>client</param-value>
</context-param>
<welcome-file-list>
<welcome-file>faces/default.xhtml</welcome-file>
</welcome-file-list>
<context-param>
<param-name>javax.servlet.jsp.jstl.fmt.localizationContext</param-name>
<param-value>resources.application</param-value>
</context-param>
<listener>
<listener-class>com.sun.faces.config.ConfigureListener</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<listener>
<listener-class>
org.springframework.web.context.request.RequestContextListener
</listener-class>
</listener>
</web-app>
面孔-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<faces-config
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-facesconfig_2_0.xsd"
version="2.0">
<application>
<el-resolver>
org.springframework.web.jsf.el.SpringBeanFacesELResolver
</el-resolver>
</application>
<managed-bean>
<managed-bean-name>user</managed-bean-name>
<managed-bean-class>p.UserBean</managed-bean-class>
<managed-bean-scope>session</managed-bean-scope>
<managed-property>
<property-name>userBo</property-name>
<value>#{userBo}</value>
</managed-property>
</managed-bean>
</faces-config>
我上面的听众有这个警告:
Class org.springframework.web.jsf.el.SpringBeanFacesELResolver must extend the type javax.el.ELResolver
我的问题在哪里。我找不到它。