How can I get the path of the start up folder from a batch file? The only way I found was to look in the registry but I don't think thats possible with CMD.
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这将设置STARTUP为启动文件夹的位置：
for /F "skip=4 tokens=3*" %%j in ('reg query "HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders" /v "Common Startup"') do set STARTUP=%%k
（skip=4适用于 XP，skip=2适用于 Windows 7。我没有 vista 来尝试那里的命令）
也可用（更改 /v 之后的值）
Common AppData
Common Programs
Common Documents
Common Desktop
Common Start Menu
CommonPictures
CommonMusic
CommonVideo
Common Templates
Common Favorites
Common Startup
Common Administrative Tools
于 2012-06-25T20:58:11.663 回答
1
在windows xp中你可以这样访问
导入的CountToMainTable
CD %HOMEDRIVE%%HOMEPATH%\Start Menu\Programs\Startup
于 2012-06-23T08:54:22.130 回答