javascript - JS regex.exec() returning first find

Question

I am trying to learn how to break up this string:

var str = 'red','blue','gree'

I have this working code:

var clean = str.replace(/\'/g, "");
var elements = clean.split(',');

which produces array ["red","blue","green"] which is what i want however. id like to learn how to do this using regex.exec() method.

here is what i got:

var patt = /([^']+)/g;
var elem= patt.exec(str); 

but this returns array ["red","red"]

any ideas?

Answer 1

使用exec, 要获得多个匹配项，您需要循环运行它...

var str = "'red','blue','gree'"; // making a guess here

var patt = /([^']+)/g;
var match;

       //   v----yes, an assignment
while(match = patt.exec(str)) {
    console.log(match[1]);
}

演示：http: //jsfiddle.net/D62D4/

全局正则表达式将最后一次匹配结束后的索引存储在自身上，并从该点开始执行下一个查询。

这一直持续到没有匹配项，此时索引设置回0.

.lastIndex您可以使用该属性在正则表达式上观察和修改此索引。