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我有一个工作文件重命名 java 工具，现在我想添加一个 if 条件来运行命令行命令，如果我选中一个框作为它重命名的每个文件的重命名过程的一部分。

稍后我将更改 dos 代码，但我发现它是一个有效的示例。我的部分问题是我的文件重命名是它自己的类，所以我还需要弄清楚如何组合这个类或以某种方式从我的主重命名类中引用 dos 命令。

更新

我用答案中的更改更新了代码，但是命令行命令不起作用，它使 java 崩溃而没有错误。该命令确实从 cmd 行工作。

import java.io.IOException;
import java.io.InputStream;

public class doscommandrun {
     public static void run() {  
         final String dosCommand = "cmd converter.exe file.doc -android -o file.txt";
            try {
                final Process process = Runtime.getRuntime().exec(
                        dosCommand + " ");
                final InputStream in = process.getInputStream();
                int ch;
                    while((ch = in.read()) != -1) {
                        System.out.print((char)ch);
                    }
                    } catch (IOException e) {
                        e.printStackTrace();
            }
        }
    }

enter code here文件重命名代码：

private void renameFile(){

    boolean operationResult = false;
    boolean overallResult = true;
    int failCount = 0;

    /* the operation of this part is ensured by the chooseDirectory()
     * WE get the list of files in the directory
     * get the conditions set by users
     * and perform the file rename operation.
     */

    //Let's get all the information from user
    String[] fileList = directory.list();  //the list of files in the directory
    String Prefix = txtPrefix.getText();
    String Rename = txtRename.getText();
    String Suffix = txtSuffix.getText();
    String digits = (String) cboSequence.getSelectedItem();
    int StartingNum;
    String generatedSequence;
    File oldFile;

    //let's call the output frame
    if(cbxOutput.isSelected() && OUTPUT_ON == false){
        buildOutput();
        OUTPUT_ON = true;
    }




    //display the list of files and readability of each file
    for(int i = 0; i < fileList.length; i++){   
        oldFile = new File(directory.getPath()+"/"+ fileList[i]);
        String readability = fileList[i] +" - readable?: "+oldFile.canRead();
        System.out.println(readability);

        if(OUTPUT_ON)
            txaOutput.append("\n"+readability);
    }

    for(int i = 0; i < fileList.length; i++){

        /* get the file extension that we need, and form a new name, 
         * we would check if the Ignore File Extension is selected
         */
        oldFile = new File(directory.getPath()+"/"+ fileList[i]);

        String fileExtension;

        if(cbxIgnoreExtension.isSelected() == true ){
            fileExtension = "";
        }
        else
            fileExtension = getFileExtension(fileList[i]);

        //this part get the original filename       
        String fileName = getFileName(fileList[i]);



        String inputInfo = "The input filename->"+ fileList[i] + "\nfile name->" + fileName + "\nextension->" + fileExtension;   
        System.out.println(inputInfo);

        if(OUTPUT_ON)
            txaOutput.append("\n"+inputInfo);



        /* generate sequence for the Name
         *if the digits selection is NONE, we ignore it
         */
        if(digits.equals("None") == true){
            generatedSequence = "";
        }
        else{
            StartingNum = Integer.parseInt(txtSequence.getText());
            generatedSequence = nameSequence(StartingNum + i, digits);
        }




        //this is affected by the RenameOption, if Rename has something then only we RENAME
        if(cbxRename.isSelected() == true){
            fileName = Rename + generatedSequence;   //the fileName will change.
        }
        else{
            //if Rename has nothing, but the txtSequence has some Value, we take it to the naming too
            fileName = fileName.substring(0,4)+ generatedSequence;
            if(cbxAndroid.isSelected() == true ){
                doscommandrun.run();
                }



        //the New File Name
        String newFileName = Prefix + fileName.substring(0,4) + Suffix + fileExtension;
        String tentativeName = "new Filename will be ->"+newFileName+"\n";
        System.out.println(tentativeName);

        if(OUTPUT_ON)
            txaOutput.append("\n"+tentativeName);




        // ! Perform the file rename, if the Experimental Mode is not selected
        if(cbxExperiment.isSelected() == false){

            operationResult = oldFile.renameTo(new File(directory.getPath()+"/"+newFileName));
            String renameResult = "\t*Rename successfully?: " + operationResult+"\n\n";
            System.out.println(renameResult);
                if(operationResult == false)
                    failCount++;

                if(OUTPUT_ON)
                    txaOutput.append("\n"+renameResult);

            //make up the overall result
            overallResult = (operationResult && overallResult);
        }

    }

    if(cbxExperiment.isSelected() == false){
        System.out.println("Overall Result: "+overallResult);
        if(overallResult)
            JOptionPane.showMessageDialog(null, "All files renamed successfully!");
        else
            JOptionPane.showMessageDialog(null, "File renamed with "+ failCount+ " failure(s)");
    }//end if
    }

}//end renameFile
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2 回答 2

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您可以在调用的 doccommandrun 类中创建一个静态方法，该方法将在调用run()时执行当前在 main 方法中的内容。

public class DosCommandRun 
{
   public static void run() 
   {
      //..do stuff from main
   }
}

现在，每当您想调用 dos 命令时，您都可以将其插入DosCommandRun.run()代码中。

于 2012-06-22T19:05:10.960 回答
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我在我的 renametool 类中的 cmd 之后添加 /c

我仍然有问题，但枯萎了一个不同的问题。

于 2012-06-22T22:27:43.610 回答