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我有一个算法可以在单元格中找到一个值，对于这种情况，可以说单元格是 C10。我需要在 D 列中的旁边查看一个值，如果该值与我需要的不匹配，则从该值上移一个单元格并检查匹配等。到目前为止，我有这个：

bits = [] 

for row in ws.iter_rows(row_offset=4,column_offset=3):
    #skip over empty rows
    if row:
        #current cell is in column C
        cell = row[2]
        try:
            #find the lowest address in the excel sheet
            if cell.internal_value == min(address):
                #somehow match up in column d
                for '''loop and search col D''':
                    if str(row[3].internal_value).upper == ('CONTROL 1' or 'CON 1'):
                        #add bits
                        for cell in row[4:]:
                            bits.append(cell.internal_value)    
        #pass over cells that aren't a number, ie values that will never match an address
        except ValueError:
            pass
        except TypeError:
            pass

有没有办法做到这一点？我知道使用row[3]D 列中的比较进行比较，但如果第一次不正确，我不知道如何上列。或者换句话说，改变行中的值row[value]，我需要知道什么值/如何在列中移动。

谢谢！

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1 回答 1

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bits = []
min_address = False
for row in ws.iter_rows(row_offset=4,column_offset=3):
    c = row[2]
    d = row[3]
    if not d.internal_value: #d will always have a value if the row isn't blank
        if min_address: 
            break #bits is what you want it to be now
        bits = [] #reset bits every time we hit a new row
        continue #this will just skip to next row

    for bits_cell in row[4:]:
        if bits_cell.internal_value:
            bits.append(bits_cell.internal_value)
    if c.internal_value:
        if c.internal_value == min(address):
            min_address = True #we set it to true, then kept going until blank row
于 2012-06-25T17:36:53.133 回答