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我有一个奇怪的问题。我有一个我想添加到应用程序的 my-spring.xml 文件,但由于某种原因,我只能在它位于根上下文中时才能检测到它。

以下未检测到根上下文中声明的 my-spring.xml。

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" 
         version="2.4">

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
        /WEB-INF/my-datasources.xml
        /WEB-INF/my-spring.xml
        </param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>myservice</servlet-name>
        <servlet-class>org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/webservice-config.xml</param-value>
        </init-param>
    </servlet>

    <servlet-mapping>
        <servlet-name>myservice</servlet-name>
        <url-pattern>/webservice/*</url-pattern>
    </servlet-mapping>

    <mime-mapping>
        <extension>wsdl</extension>
        <mime-type>text/xml</mime-type>
    </mime-mapping>

    <mime-mapping>
        <extension>xsd</extension>
        <mime-type>text/xml</mime-type>
    </mime-mapping>

</web-app>

如果我把它改成这个,那么它就可以工作(注意 my-spring.xml 的位置不同)。

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" 
         version="2.4">

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
        /WEB-INF/my-datasources.xml
        </param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>myservice</servlet-name>
        <servlet-class>org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/webservice-config.xml</param-value>
                <param-value>/WEB-INF/my-spring.xml</param-value>
        </init-param>
    </servlet>

    <servlet-mapping>
        <servlet-name>myservice</servlet-name>
        <url-pattern>/webservice/*</url-pattern>
    </servlet-mapping>

    <mime-mapping>
        <extension>wsdl</extension>
        <mime-type>text/xml</mime-type>
    </mime-mapping>

    <mime-mapping>
        <extension>xsd</extension>
        <mime-type>text/xml</mime-type>
    </mime-mapping>

</web-app>

我真的看不出我做错了什么。如果我理解它的工作方式,当在根上下文中声明时(如第一个示例),它应该由应用程序的任何资源访问。在此示例中似乎并非如此,因为我无法从 Controller/Endpoint 类访问 my-spring.xml 文件中定义的属性。

4

2 回答 2

1

我认为您需要逗号来分隔多个contextConfigLocation文件。基于这个答案:https ://stackoverflow.com/a/2725413/116509

编辑:尝试删除前面的/egWEB-INF/my-datasources.xml而不是/WEB-INF/my-datasources.xml

于 2012-06-22T11:07:07.587 回答
1

尝试这样的事情

<context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            classpath:/my-datasources.xml
            classpath:/my-spring.xml
        </param-value>
</context-param>

但是你必须在类路径中有这两个文件

于 2012-06-22T11:49:32.043 回答