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我正在创建一个应用程序，当您按下屏幕上的一系列按钮时播放音符。还有一个按钮可以在按下时播放一系列音符（最多 10 个音符）。该应用程序起初运行良好。但是，如果您要播放一系列音符并且连续按下播放按钮几次，则应用程序最终将强制关闭。任何帮助将不胜感激。

private final int duration = 1; // seconds 
private final int sampleRate = 10000; 
private final int numSamples = duration * sampleRate; 
private final double sample[] = new double[numSamples]; 
private double freqOfTone; // hz 

private final byte generatedSnd[] = new byte[2 * numSamples];

 public void onPlayButtonClick(View v){
    playMultiNoteSound();
}
synchronized void playMultiNoteSound(){

    CharSequence chrs1;
    TextView lblNoteList;
    lblNoteList=(TextView)findViewById(R.id.lblNoteList);
    chrs1=lblNoteList.getText();

    for(int i=0;i<chrs1.length();i++){
        final int int1=i;

        Thread thrdPlay=new Thread(new Runnable(){

            public void run(){
                int minSize =AudioTrack.getMinBufferSize( sampleRate, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_16BIT );
                audioTrack = new AudioTrack(AudioManager.STREAM_MUSIC, 
                        sampleRate, AudioFormat.CHANNEL_CONFIGURATION_MONO, 
                        AudioFormat.ENCODING_PCM_16BIT, minSize, 
                        AudioTrack.MODE_STREAM);
                char chrCurrent;
                CharSequence chrs;


                TextView lblNoteList;
                lblNoteList=(TextView)findViewById(R.id.lblNoteList);
                chrs=lblNoteList.getText();
                chrCurrent=chrs.charAt(int1);
                Double[]allTones;
                allTones= new Double[chrs.length()];
                allTones[int1]=getToneForText(chrCurrent);
                byte[] results;
                results=genSelectTone(allTones[int1]);
                audioTrack.write(results, 0, results.length);
                audioTrack.setStereoVolume(1.0f, 1.0f);
                audioTrack.play();
                if(audioTrack.getPlayState()==AudioTrack.PLAYSTATE_STOPPED){
                    audioTrack.stop();
                    audioTrack.release();
                }
            }
        });
        thrdPlay.setDaemon(true);   
         thrdPlay.start();
         try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        if(thrdPlay!=null){
            thrdPlay.stop();
            thrdPlay=null;
        }
        }

}
public double getToneForText(char val){
    Float dblResult;
    dblResult=0f;
    switch (val){
    case '1':
        dblResult=261.63f;
        break;
    case '2':
        dblResult=293.66f;
        break;
    case '3':
        dblResult=329.63f;
        break;
    case '4':
        dblResult=349.23f;
        break;
    case '5':
        dblResult=392.0f;
        break;
    case '6':
        dblResult=440.0f;
        break;
    case '7':
        dblResult=493.88f;
        break;
    case '8':
        dblResult=523.25f;
        break;
    case '9':
        dblResult=587.33f;
        break;
    case '0':
        dblResult=659.26f;
        break;
    }       
    return dblResult;
}

我相信这就是所有相关的代码。如果您需要其他信息/代码，请告诉我。

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1 回答 1

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您不应该为每次迭代重新初始化audioTrack。而是在循环之前对其进行初始化并在循环中使用audioTrack.write。您只是在不填充缓冲区的情况下重新初始化它。

其次，作为一个提议，你不应该更新 gui 并在同一个线程中播放声音。尝试AsyncTask改用。

于 2013-02-25T19:12:51.957 回答