3

给定DateTime start = startsomethingDateTime end = endSomething

是否有一种标准方法可以返回开始和结束内的所有日期,以便返回是一个日期列表,如...

'1/1/2012 12:00 AM'
'1/2/2012 12:00 AM'
4

4 回答 4

5

您可以创建这样的方法:

public static IEnumerable<DateTime> Range(DateTime start, DateTime end) {
  for (var dt = start; dt <= end; dt = dt.AddDays(1)) {
    yield return dt;
  }
}
于 2012-06-22T02:59:52.247 回答
3

您可以填写所有日期的列表:

DateTime begin = //some start date
DateTime end = //some end date
List<DateTime> dates = new List<DateTime>();
for(DateTime date = begin; date <= end; date = date.AddDays(1))
{
    dates.Add(date);
}
于 2012-06-22T02:58:51.843 回答
3

Linq方式:

DateTime start = new DateTime(2012, 1, 1);
DateTime end = new DateTime(2012, 6, 1);

var list = Enumerable.Range(0, (end - start).Days + 1).Select(i => start.AddDays(i));
于 2012-06-22T03:03:58.370 回答
0

您可以使用它来生成日期范围

public static IEnumerable<DateTime> GetDateRange(DateTime startDate, DateTime endDate)
{
  if (endDate < startDate)
    throw new ArgumentException("endDate must be greater than or equal to startDate");

  while (startDate <= endDate)
  {
    yield return startDate;
    startDate = startDate.AddDays(1);
  }
}

然后

GetDateRange(startDate,endDate).Select(d => d.ToString("dd/MM/yyyy hh:mm")).ToArray();
于 2012-06-22T03:05:47.740 回答