我会使用 PROC TRANSPOSE,以便可以轻松比较每组中的值。例如:
data groups1;
input id $ grp age sex $;
datalines;
1 1 60 M
2 1 21 M
3 2 30 M
4 2 25 F
5 3 45 F
6 3 30 F
7 3 18 M
8 4 32 M
9 4 18 M
10 4 16 M
;
run;
proc sort data=groups1;
by grp; /* This maintains age order */
run;
proc transpose data=groups1 out=groups2;
by grp;
var age;
run;
使用转置后的数据,您可以进行任何您喜欢的比较(我无法从您的问题中看出您到底想要什么,所以我只比较前两个年龄):
/* With all ages of a particular group in a single row, it is easy to compare */
data outgroups1(keep=grp);
set groups2;
if abs(col1-col2)>5 then output;
run;
在这种情况下,这将是我为满足任何应用条件的每个组创建单独数据集的首选方法(动态生成和包含代码):
/* A separate data set per GRP value in OUTGROUPS1 */
filename dynacode catalog "work.dynacode.mycode.source";
data _null_;
set outgroups1;
file dynacode;
put "data grp" grp ";";
put " set groups1(where=(grp=" grp "));";
put "run;" /;
run;
%inc dynacode;