python - 如何在python中比较2个json

Question

下面如何在 python 中比较 2 个 json 对象是示例 json。

sample_json1={
    {
       "globalControlId": 72,
       "value": 0,
       "controlId": 2
   },
   {
       "globalControlId": 77,
       "value": 3,
       "controlId": 7
   }
}

sample_json2={
    {
       "globalControlId": 72,
       "value": 0,
       "controlId": 2
   },
   {
       "globalControlId": 77,
       "value": 3,
       "controlId": 7
   }
}

Answer 1

似乎通常的比较工作正常

import json
x = json.loads("""[
    {
       "globalControlId": 72,
       "value": 0,
       "controlId": 2
   },
   {
       "globalControlId": 77,
       "value": 3,
       "controlId": 7
   }
]""")

y = json.loads("""[{"value": 0, "globalControlId": 72,"controlId": 2}, {"globalControlId": 77, "value": 3, "controlId": 7 }]""")

x == y # result: True    

Answer 2

这些不是有效的 JSON / Python 对象，因为数组 / 列表文字在里面[]而不是{}：

更新：比较字典列表（序列化的 JSON 对象数组），同时忽略列表项的顺序，列表需要排序或转换为集合：

sample_json1=[{"globalControlId": 72, "value": 0, "controlId": 2},
              {"globalControlId": 77, "value": 3, "controlId": 7}]
sample_json2=[{"globalControlId": 77, "value": 3, "controlId": 7},
              {"globalControlId": 77, "value": 3, "controlId": 7}, # duplicity
              {"globalControlId": 72, "value": 0, "controlId": 2}]

# dictionaries are unhashable, let's convert to strings for sorting
sorted_1 = sorted([repr(x) for x in sample_json1])
sorted_2 = sorted([repr(x) for x in sample_json2])
print(sorted_1 == sorted_2)

# in case the dictionaries are all unique or you don't care about duplicities,
# sets should be faster than sorting
set_1 = set(repr(x) for x in sample_json1)
set_2 = set(repr(x) for x in sample_json2)
print(set_1 == set_2)