php - Using php and mongodb, how do you remove a document by type

Question

I have read the documentation and searched all over but I can't find how to do it. If I have a document inside a collection and the document is an empty array I can remove it like this:

db.data.remove(array('document'=>array()))

or like this:

db.data.remove(array('document'=>[]))

But if the array is not empty it doesn't work, so I tried like this:

db.data.remove(array('document'=>array('$type'=>4)))

Am I doing it wrong? Is there any way to do this? Removing the document on another criteria isn't useful for me.

Answer 1

编辑： 最后我发现你的问题是什么。

// test document
{ "_id" : ObjectId("4fe1af4dd404b1863ff20aac"), "document" : [ 1 ] }

运算符查看数组内部，而$type不是数组本身，因此以下 find 不返回任何内容：

db.test.find({document : { $type : 4  } })

现在在我的测试用例中，该文档包含一个双精度，以下查找返回该文档：

db.test.find({document : { $type : 1  } })
{ "_id" : ObjectId("4fe1af4dd404b1863ff20aac"), "document" : [ 1 ] }

另请参阅有关此主题的错误报告： https ://jira.mongodb.org/browse/SERVER-1475